[PHP开发] 我写一个简单的图片路径存储到mysql然后PHP显示图片的例子

test1.php:

<?php
header("Content-type:text/html;charset=UTF-8");
$a=mysql_connect("localhost","tushuai","123456");
$link = mysql_select_db("cty_test",$a);

$sql="CREATE TABLE image_sql(ID int Not Null AUTO_INCREMENT, primary key(ID), ImageName varchar(30), Image blob)";
mysql_query($sql, $a);

mysql_query("insert into image_sql(ID, ImageName, Image)
values(1, 'IPHONE车展名模', 'images/29.jpg')");

mysql_query("insert into image_sql(ID, ImageName, Image)
values(2, 'IPAD案例演示', 'images/48.jpg')");

mysql_query("insert into image_sql(ID, ImageName, Image)
values(3, 'IPAD日历演示', 'images/49.jpg')");

mysql_query("insert into image_sql(ID, ImageName, Image)
values(4, 'IPAD杂志演示', 'images/50.jpg')");

mysql_query("insert into image_sql(ID, ImageName, Image)
values(5, 'IPAD游戏演示', 'images/52.jpg')");

mysql_query("insert into image_sql(ID, ImageName, Image)
values(6, '疯狂农场', 'images/53.jpg')");

mysql_query("insert into image_sql(ID, ImageName, Image)
values(7, '虚拟社区商场', 'images/54.jpg')");
mysql_query("insert into image_sql(ID, ImageName, Image)
values(8, '脸谱拼图', 'images/55.jpg')");

mysql_close($a);

?>

test2.php:
<?php
header("Content-type:text/html;charset=UTF-8");
$a=mysql_connect("localhost","tushuai","123456");
if(!$a)
{
die(mysql_error());
}
mysql_select_db("cty_test", $a);
$b=mysql_query("select * from image_sql");

while($c=mysql_fetch_array($b))
{
echo $c['ImageName']."<img src=".$c['Image']." />";
echo "<br />";
}
mysql_close($a);

?>
posted @ 2016-06-14 16:31  江南落幕  阅读(795)  评论(0编辑  收藏  举报