LeetCode 27 Remove Element
题目:
Given an array nums and a value val, remove all instances of that value in-placeand return the new length.
Do not allocate extra space for another array, you must do this by modifying the input array in-place with O(1) extra memory.
The order of elements can be changed. It doesn't matter what you leave beyond the new length.
Example 1:
Given nums = [3,2,2,3], val = 3, Your function should return length = 2, with the first two elements of nums being 2. It doesn't matter what you leave beyond the returned length.
Example 2:
Given nums = [0,1,2,2,3,0,4,2], val = 2, Your function should return length =5
, with the first five elements ofnums
containing0
,1
,3
,0
, and 4. Note that the order of those five elements can be arbitrary. It doesn't matter what values are set beyond the returned length.
解法:
在数组中原地删除等于指定值的元素,一个下标i用于遍历数组,一个下标k指示新数组的位置
class Solution { public int removeElement(int[] nums, int val) { int k=0; for(int i=0;i<nums.length;i++) { if(nums[i]!=val) nums[k++] = nums[i]; } return k; } }