LeetCode 27 Remove Element

题目：

Given an array nums and a value val, remove all instances of that value in-placeand return the new length.

Do not allocate extra space for another array, you must do this by modifying the input array in-place with O(1) extra memory.

The order of elements can be changed. It doesn't matter what you leave beyond the new length.

Example 1:

Given nums = [3,2,2,3], val = 3,

Your function should return length = 2, with the first two elements of nums being 2.

It doesn't matter what you leave beyond the returned length.

Example 2:

Given nums = [0,1,2,2,3,0,4,2], val = 2,

Your function should return length = 5, with the first five elements of nums containing 0, 1, 3, 0, and 4.

Note that the order of those five elements can be arbitrary.

It doesn't matter what values are set beyond the returned length.

解法：

在数组中原地删除等于指定值的元素，一个下标i用于遍历数组，一个下标k指示新数组的位置

class Solution {
    public int removeElement(int[] nums, int val) {
        int k=0;
        
        for(int i=0;i<nums.length;i++)
        {
            if(nums[i]!=val)
                nums[k++] = nums[i];
        }
        return k;
    }
}