【C++学习】引用变量

1. 引用变量必须在声明时初始化,且之后无法更改(更改指的是成为其他变量的引用,即:引用变量一旦与某个变量关联起来,就一直效忠于它)

类似于const 指针:

int a = 10;
int & re = a;  //re的引用不可变
int * const pr = &a; // pr的指向不可变 

 

 1 #include <iostream>
 2 using namespace std;
 3 
 4 int main()
 5 {
 6     int a = 101;
 7     int b = 50;
 8     int & re = a;
 9     cout << "a value: " << a << endl;
10     cout << "a address: " << &a << endl;
11     cout << "b value: " << b << endl;
12     cout << "b address: " << &b << endl;
13     cout << "re value: " << re << endl;
14     cout << "re address: " << &re << endl;
15     re = b; //这里只是将b的值赋值给re引用的变量(a),无法让re引用新的变量(b)
16     cout << "a value: " << a << endl;
17     cout << "a address: " << &a << endl;
18     cout << "b value: " << b << endl;
19     cout << "b address: " << &b << endl;
20     cout << "re value: " << re << endl;
21     cout << "re address: " << &re << endl;
22     return 0;
23 }
24 /*
25 输出
26 a value: 101
27 a address: 0x6dfee8
28 b value: 50
29 b address: 0x6dfee4
30 re value: 101
31 re address: 0x6dfee8
32 a value: 50
33 a address: 0x6dfee8
34 b value: 50
35 b address: 0x6dfee4
36 re value: 50
37 re address: 0x6dfee8
38 */
例1
 1 #include <iostream>
 2 using namespace std;
 3 
 4 int main()
 5 {
 6     int a = 101;
 7     int * pt = &a;
 8     int & re = *pt;
 9     cout << "pt: " << pt << endl;
10     cout << "re: " << &re << endl;
11     cout << "a: " << &a << endl;
12     int b = 50;
13     pt = &b;  // pt指向b, 但是re仍然是a的引用
14     cout << "pt: " << pt << endl;
15     cout << "re: " << &re << endl;
16     cout << "a: " << &a << endl;
17     cout << "b:" << &b << endl;
18     return 0;
19 }
20 
21 /*
22 输出
23 pt: 0x6dfee4
24 re: 0x6dfee4
25 a: 0x6dfee4
26 pt: 0x6dfee0
27 re: 0x6dfee4
28 a: 0x6dfee4
29 b:0x6dfee0
30 */
例2
posted @ 2021-06-27 17:27  萌新的学习之路  阅读(146)  评论(0编辑  收藏  举报