c# float类型和double类型相乘出现精度丢失

c# float类型和double类型相乘出现精度丢失

            double db = 4.0;
            double db2 = 1.3;
            float f = 1.3F;
            float f2 = 4.0F;
            Decimal de = Convert.ToDecimal(f);
            MessageBox.Show("double * float " + (db * f).ToString() + "\r\n double * double " + (db * db2).ToString());
            MessageBox.Show("double * (double)float " + (db * Convert.ToDouble(f)).ToString() + "\r\n float * float " + (f * f2).ToString()
                + "\r\n (Decimal)double * (Decimal)float " + (Convert.ToDecimal(db) * Convert.ToDecimal(f)).ToString());
            //Convert.ToDecimal(db)转化成Decimal类型计算,Decimal 128位高精度浮点数,常用于金融运算,不会出现浮点数计算的误差

本文解决办法参考http://www.cnblogs.com/quietwalk/archive/2010/05/02/1725885.html

posted @ 2017-02-28 16:09  漫天行  阅读(1969)  评论(0编辑  收藏  举报