shell字符串拼接2，作为结果传递参数

打印日志需涵盖很多固定输出，所以我shell输出调用函数，也就是把特定字符串传给打印函数

 

存在一个问题，就是字符串包含空格时，只输出第一个空格前的内容。我盲猜，可能作为多个参数了。

 

不作为函数参数时，可以正常输出

$cat aaa.sh 
#! /bin/bash

pack=""
tmp1="apple banana"
tmp2="orange"
pack=${pack}${tmp1}" "
pack=${pack}${tmp2}" "
echo ${pack}
$ ./aaa.sh 
apple banana orange

作为参数时，输出有毛病

$cat ccc.sh 
#! /bin/bash

function print()
{
        echo $1
}
pack=""
tmp1="apple banana"
tmp2="orange"
pack=${pack}${tmp1}" "
pack=${pack}${tmp2}" "

print $pack
$./ccc.sh 
apple

错误改法+验证

$cat ddd.sh 
#! /bin/bash

IFS_BACKUP=$IFS
function print()
{
        IFS=$(echo -en "\n\b")
        echo $1 $2
        IFS=$IFS_BACKUP
}
pack=""
tmp1="apple banana"
tmp2="orange"
pack=${pack}${tmp1}" "
pack=${pack}${tmp2}" "

print $pack
$ ./ddd.sh 
apple banana

正确改法

$ cat fff.sh 
#! /bin/bash

IFS_BACKUP=$IFS
function print()
{
        echo $1
}
pack=""
tmp1="apple banana"
tmp2="orange"
pack=${pack}${tmp1}" "
pack=${pack}${tmp2}" "
        IFS=$(echo -en "\n\b")

print $pack

        IFS=$IFS_BACKUP
$ ./fff.sh 
apple banana orange 

 最后，一个测试

$ cat ggg.sh
#! /bin/bash

IFS_BACKUP=$IFS
function print()
{
echo $1
}
pack=""
tmp1="apple banana"
tmp2="orange"
pack=${pack}${tmp1}" "
pack=${pack}${tmp2}" "

print 'apple orange yellow'
print "apple orange yellow"
print $pack
print '$pack'
print "$pack"
$./ggg.sh
apple orange yellow
apple orange yellow
apple
$pack
apple banana orange

 https://www.jb51.net/article/179534.htm