Cordic 算法之 反正切

在通信的算法中,常采用Cordic算法之一,知道角度产生正交的的正弦余弦,

或者知道正弦和余弦求角度,求反正切。

1. 求正弦和余弦值。

    方法:旋转角度,得到正弦余弦值; 再旋转角度,到达下一个正弦余弦值;直到旋转的角度趋近于 0 ,不能再进行旋转。

把每次旋转的坐标的x,Y 轴的值各自相加,即得到为该角度的正弦和余弦值。

2 .求反正切:Angle  = artan(y/x)。

    方法: 及给定x,y 的坐标通过向量旋转,使得y 值不断减小, 通过不断地迭代使得 y 逐渐 趋渐0;

最终得到旋转的角度之和 z, z 即为 反正切值。

验证 输入y=5000, x=5000;通过计算 atan(5000/5000) =0.5(pi 弧度)*90度 = 45度。

 

验证 输入y=6000, x=4000;通过计算 atan(6000/4000) =0.626(pi 弧度)* 90度 = 56.3度

 

 

验证 输入y=6000, x=500;通过计算 atan(6000/0500) =0.947(pi 弧度)* 90度 = 85.23度。

 

 

//level 1
always@(posedge clk or negedge rst_n)
begin
        if(!rst_n)
               begin
                       x1<=0;
                       y1<=0;
                       z1<=0;
               end
         else
                if(ena)
                       if(y0<0)
                               begin
                                      x1<=x0-y0;
                                      y1<=y0+x0;
                                      z1<=z0-15'd4500;  //45deg
                               end
                      else if(y0>0)
                               begin
                                      x1<=x0+y0;
                                      y1<=y0-x0;
                                      z1<=z0+15'd4500;  //45deg 
                              end 
                      else 
                          begin
                              x1 <= x0;
                              y1 <= y0;
                              z1 <= z0;
                          end 
end

//level 2
always@(posedge clk or negedge rst_n)
begin
        if(!rst_n)
               begin
                       x2<=0;
                       y2<=0;
                       z2<=0;
               end
         else
                if(ena)
                       if(y1<0)
                               begin
                                      x2<=x1-{y1[DATA_WIDTH-1],y1[DATA_WIDTH-1:1]};
                                      y2<=y1+{x1[DATA_WIDTH-1],x1[DATA_WIDTH-1:1]};
                                      z2<=z1-15'd2656;  //26.56deg
                                     
                               end
                        else if(y1>0)
                               begin
                                      x2<=x1+{y1[DATA_WIDTH-1],y1[DATA_WIDTH-1:1]};
                                      y2<=y1-{x1[DATA_WIDTH-1],x1[DATA_WIDTH-1:1]};
                                      z2<=z1+15'd2656;
                               end
                      else
                               begin
                                 x2 <= x1;
                                 y2 <= y1;
                                 z2 <= z1;
                                 end
end

...

...

...

 

//level 13
always@(posedge clk or negedge rst_n)
begin
        if(!rst_n)
                 begin
                       x13<=0;
                       y13<=0;
                       z13<=0;
               end
         else
                if(ena)
                       if(y12<0)
                               begin
                                      x13<=x12-{{12{y12[DATA_WIDTH-1]}},y12[DATA_WIDTH-1:12]};
                                      y13<=y12+{{12{x12[DATA_WIDTH-1]}},x12[DATA_WIDTH-1:12]};
                                      z13<=z12-15'd01;  //0.014deg
                               end
                        else if(y12>0)
                              begin
                                      x13<=x12+{{12{y12[DATA_WIDTH-1]}},y12[DATA_WIDTH-1:12]};
                                      y13<=y12-{{12{x12[DATA_WIDTH-1]}},x12[DATA_WIDTH-1:12]};
                                      z13<=z12+15'd01;
                               end
                             else
                               begin
                                    x13 <= x12;
                                    y13 <= y12;
                                    z13 <= z12;
                                 end
end

posted @ 2014-03-09 19:45  乐富道  Views(8467)  Comments(1Edit  收藏  举报