摘要: 1 void diffOddAndEven(int a[], int n) { 2 int low = 0, high = n - 1; 3 int pivot; 4 while (low < high) { 5 while (a[high] % 2 == ... 阅读全文
posted @ 2015-08-03 16:14 Tony-Hu 阅读(137) 评论(0) 推荐(0) 编辑