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Algorithms, Distributed System, Machine Learning

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12 2017 档案

摘要:Fancy, classic, STEP-BY-STEP Analysis strategy problem. Here is the approach: 1. Sort input arrays.. so sum[0] is a[0] * k, so we got a[0]2. Then who 阅读全文
posted @ 2017-12-30 03:55 Tonix 阅读(237) 评论(0) 推荐(0)

摘要:Classic problem to learn Game Theory - an advanced one: how to identify sub-games.. For every move (hit 1\2 bins) on one continuous section, the origi 阅读全文
posted @ 2017-12-29 13:17 Tonix 阅读(254) 评论(0) 推荐(0)

摘要:DFS + memo. 阅读全文
posted @ 2017-12-29 09:09 Tonix 阅读(243) 评论(0) 推荐(0)

摘要:Actually, it is a Greedy problem : ) 阅读全文
posted @ 2017-12-29 08:45 Tonix 阅读(133) 评论(0) 推荐(0)

摘要:It is marked as Recursion on HR, but the optimal solution is DP. Step by step, discover internal mechanism. 阅读全文
posted @ 2017-12-28 13:45 Tonix 阅读(142) 评论(0) 推荐(0)

摘要:The trick of this problem is.. Adding 1+ coins to one pile, means nothing - you add one, then i just remove it.. so it is back to original game. So, b 阅读全文
posted @ 2017-12-27 12:29 Tonix 阅读(141) 评论(0) 推荐(0)

摘要:A simple NIM game in disguise: move 1 coin to one of previous slot, equals to removing.. Then no surprise, Sprague-Grundy theorem solves the problem. 阅读全文
posted @ 2017-12-27 11:55 Tonix 阅读(181) 评论(0) 推荐(0)

摘要:Another easy one solved by Sprague-Grundy theorem. Each pile is a sub-game, so you need to XOR SG value of all substates - since you can move # of 1 - 阅读全文
posted @ 2017-12-27 11:37 Tonix 阅读(144) 评论(0) 推荐(0)

摘要:A matter of OBSERVATION.. draw a triangle of parity, and watch. 阅读全文
posted @ 2017-12-27 08:46 Tonix 阅读(110) 评论(0) 推荐(0)

摘要:Discrete thinking - Play & Observe! " you can move numbers in any quadrant at the following positions to [x][y]: [x][y] or // upper left quadrant [x][ 阅读全文
posted @ 2017-12-26 13:43 Tonix 阅读(196) 评论(0) 推荐(0)

摘要:Another intuitive of application of Sprague-Grundy theorem. 阅读全文
posted @ 2017-12-26 13:18 Tonix 阅读(204) 评论(0) 推荐(0)

摘要:An intuitive problem for learning & applying Sprague-Grudy theorem: https://zhuanlan.zhihu.com/maigo/20611132 Lesson learnt, in Sprague-Grundy theorem 阅读全文
posted @ 2017-12-26 11:12 Tonix 阅读(214) 评论(0) 推荐(0)

摘要:The major trick is from another similar HR problem: subarray with max XOR: Build a binary tree bit by bit, and go from MSB to LSB, greedily. In this o 阅读全文
posted @ 2017-12-25 12:13 Tonix 阅读(243) 评论(0) 推荐(0)

摘要:Fun Greedy. My first thought was a DFS based solution... however the editorial provides a super neat 2-pass O(n) solution: Pass 1: if s[l] != s[r], ch 阅读全文
posted @ 2017-12-23 10:32 Tonix 阅读(124) 评论(0) 推荐(0)

摘要:Over-thinking will not get you there though : ) The trick is QUITE easy: # of unique chars. 阅读全文
posted @ 2017-12-22 05:30 Tonix 阅读(128) 评论(0) 推荐(0)