poj 1338 Ugly Numbers
Ugly Numbers
Time Limit: 1000MS | Memory Limit: 10000K | |
Total Submissions: 21649 | Accepted: 9680 |
Description
Ugly numbers are numbers whose only prime factors are 2, 3 or 5. The sequence
1, 2, 3, 4, 5, 6, 8, 9, 10, 12, ...
shows the first 10 ugly numbers. By convention, 1 is included.
Given the integer n,write a program to find and print the n'th ugly number.
1, 2, 3, 4, 5, 6, 8, 9, 10, 12, ...
shows the first 10 ugly numbers. By convention, 1 is included.
Given the integer n,write a program to find and print the n'th ugly number.
Input
Each line of the input contains a postisive integer n (n <= 1500).Input is terminated by a line with n=0.
Output
For each line, output the n’th ugly number .:Don’t deal with the line with n=0.
Sample Input
1 2 9 0
Sample Output
1 2 10
由题意可知这个数一定是2或3或5的倍数则每次取这三个数的倍数中最小的那个即可
注意:数据范围超过了int型 应该使用long long或者int_64
#include<stdio.h> #include<string.h> #define MAX 1510 #define min(x,y)(x<y?x:y) long long ugly[MAX]; int main() { int n,m,j,i; int a,b,c; int u2,u3,u5; u2=1;u3=1;u5=1; ugly[1]=1; for(i=2;i<MAX;i++) { a=2*ugly[u2]; b=3*ugly[u3]; c=5*ugly[u5]; ugly[i]=min(a,min(b,c)); if(ugly[i]==a) u2++; if(ugly[i]==b) u3++; if(ugly[i]==c) u5++; } while(scanf("%d",&n),n) { printf("%d\n",ugly[n]); } return 0; }