dom4j将xml转换为json

//用于判断是否有子节点,若有就将子节点也进行拼接,若无则返回"" public String checkChildEle(Element element) throws DocumentException{

String json="";

List<Element> list = new ArrayList<Element>();

list=element.elements();

if (list.size()>0) {

for (Element ele : list) {

json+=ele.getName()+":"+ele.getText()+","+"\r\n"+checkChildEle(ele); } }

return json; }

//这个方法是将xml字符串转成Json

public String xmlChangeJson(String XML) throws DocumentException{

Document document=DocumentHelper.parseText(XML);

Element root=document.getRootElement();

Iterator it=root.elementIterator();

String json="{";

while (it.hasNext()) {

Element element =(Element)it.next();

String j=checkChildEle(element);

if (j=="") { json+=element.getName()+":"+element.getText()+","+"\r\n";

}else {

json+=j;

}

}

json+="}";

return json; }

//这个方法是将xml文件转成Json

public String xmlChangeJson(File XML) throws DocumentException{

SAXReader reader=new SAXReader();

Document document=reader.read(XML);

Element root=document.getRootElement();

Iterator it=root.elementIterator();

String json="{";

while (it.hasNext()) {

Element element =(Element)it.next();

String j=checkChildEle(element);

if (j=="") {

json+=element.getName()+":"+element.getText()+","+"\r\n";

}else {

json+=j;

}

}

json+="}";

return json; }

posted on 2017-06-14 22:20  tongbug  阅读(4806)  评论(1编辑  收藏  举报