java的PreparedStatement中使用like时的问题

SQL:select * from students where name like '%tommy%';

正常的sql如上,是可以直接执行的,

那放到java的P热怕热的Statement中就应该是:

//同时把tommy改成通配符?

PreparedStatement pstmt1 = conn.prepareStatement("select * from student where name like '%?%'");

pstmt1.setString(1,"tommy");//这里居然不通过

 

解决方法一:使用拼接字符串

PreparedStatement pstmt1 = conn.prepareStatement("select * from student where name like '%"+tommy+"%'");

解决方法二:灵活变通(其实就是通配符?不能放在''单引号中)

PreparedStatement pstmt1 = conn.prepareStatement("select * from student where name like ?");

pstmt1.setString(1,"%"+"tommy"+"%");

posted @ 2014-12-23 14:54  一菲聪天  阅读(1414)  评论(0编辑  收藏  举报