java小技术之生成二维码

把我们需要的链接或者内容生成二维码其实是一件非常容易的事情，有很多办法可以实现，这里我们采用JS方法生成。

<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<html>
<head>
<script type="text/javascript" src="jquery-1.8.0.min.js"></script>
<script type="text/javascript" src="jquery.qrcode-0.12.0.min.js"></script>          //生成二维码的JS
<%@ page language="java" contentType="text/html; charset=UTF-8"
    pageEncoding="UTF-8"%>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title>生成二维码页面</title>

</head>
<body>

<div style="margin-top: 10px;width:500px;height:500px;" id="output"></div>

</body>
<script type="text/javascript">
      var url = 'https://home.cnblogs.com/u/tohxyblog/';        //生成二维码的信息，如果是URL需要自动跳转，前面一定记得带上HTTP：//
      $('#output').qrcode({render: "canvas",width:500,height:500,correctLevel:0,text:url});
   </script>
</html>

JS文件，全部拷贝即可

/* jQuery.qrcode 0.12.0 - http://larsjung.de/jquery-qrcode/ - uses //github.com/kazuhikoarase/qrcode-generator (MIT) */

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var

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is("img"

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var

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var

l=r.isDark,g=n+i,s=o+i,h=e.radius*i,v=a-1,d=a+1,w=c-1,m=c+1,p=l(a,c),y=l(v,w),T=l(v,c),B=l(v,m),A=l(a,m),E=l(d,m),k=l(d,c),M=l(d,w),C=l(a,w);p?u(t,n,o,g,s,h,!T&&!C,!T&&!A,!k&&!A,!k&&!C):f(t,n,o,g,s,h,T&&C&&y,T&&A&&B,k&&A&&E,k&&C&&M)}function l(r,t,e){

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e={MODE_NUMBER:1,MODE_ALPHA_NUM:2,MODE_8BIT_BYTE:4,MODE_KANJI:8},n={L:1,M:0,Q:3,H:2},o={PATTERN000:0,PATTERN001:1,PATTERN010:2,PATTERN011:3,PATTERN100:4,PATTERN101:5,PATTERN110:6,PATTERN111:7},i=function(){

var

t=[[],[6,18],[6,22],[6,26],[6,30],[6,34],[6,22,38],[6,24,42],[6,26,46],[6,28,50],[6,30,54],[6,32,58],[6,34,62],[6,26,46,66],[6,26,48,70],[6,26,50,74],[6,30,54,78],[6,30,56,82],[6,30,58,86],[6,34,62,90],[6,28,50,72,94],[6,26,50,74,98],[6,30,54,78,102],[6,28,54,80,106],[6,32,58,84,110],[6,30,58,86,114],[6,34,62,90,118],[6,26,50,74,98,122],[6,30,54,78,102,126],[6,26,52,78,104,130],[6,30,56,82,108,134],[6,34,60,86,112,138],[6,30,58,86,114,142],[6,34,62,90,118,146],[6,30,54,78,102,126,150],[6,24,50,76,102,128,154],[6,28,54,80,106,132,158],[6,32,58,84,110,136,162],[6,26,54,82,110,138,166],[6,30,58,86,114,142,170]],n=1335,i=7973,u=21522,f={},c=function(r){

for(var t=0;0!=r;)t+=1,r>>>=1;return t};return f.getBCHTypeInfo=function(r){for(var t=r<<10;c(t)-c(n)>=0;)t^=n<<c(t)-c(n);return(r<<10|t)^u},f.getBCHTypeNumber=function(r){for(var t=r<<12;c(t)-c(i)>=0;)t^=i<<c(t)-c(i);return r<<12|t},f.getPatternPosition=function(r){return t[r-1]},f.getMaskFunction=function(r){switch(r){case o.PATTERN000:return function(r,t){return(r+t)%2==0};case o.PATTERN001:return function(r,t){return r%2==0};case o.PATTERN010:return function(r,t){return t%3==0};case o.PATTERN011:return function(r,t){return(r+t)%3==0};case o.PATTERN100:return function(r,t){return(Math.floor(r/2)+Math.floor(t/3))%2==0};case o.PATTERN101:return function(r,t){return r*t%2+r*t%3==0};case o.PATTERN110:return function(r,t){return(r*t%2+r*t%3)%2==0};case o.PATTERN111:return function(r,t){return(r*t%3+(r+t)%2)%2==0};default:throw new Error("bad maskPattern:"+r)}},f.getErrorCorrectPolynomial=function(t){for(var e=r([1],0),n=0;t>n;n+=1)e=e.multiply(r([1,a.gexp(n)],0));return e},f.getLengthInBits=function(r,t){if(t>=1&&10>t)switch(r){case e.MODE_NUMBER:return 10;case e.MODE_ALPHA_NUM:return 9;case e.MODE_8BIT_BYTE:return 8;case e.MODE_KANJI:return 8;default:throw new Error("mode:"+r)}else if(27>t)switch(r){case e.MODE_NUMBER:return 12;case e.MODE_ALPHA_NUM:return 11;case e.MODE_8BIT_BYTE:return 16;case e.MODE_KANJI:return 10;default:throw new Error("mode:"+r)}else{if(!(41>t))throw new Error("type:"+t);switch(r){case e.MODE_NUMBER:return 14;case e.MODE_ALPHA_NUM:return 13;case e.MODE_8BIT_BYTE:return 16;case e.MODE_KANJI:return 12;default:throw new Error("mode:"+r)}}},f.getLostPoint=function(r){for(var t=r.getModuleCount(),e=0,n=0;t>n;n+=1)for(var o=0;t>o;o+=1){for(var i=0,a=r.isDark(n,o),u=-1;1>=u;u+=1)if(!(0>n+u||n+u>=t))for(var f=-1;1>=f;f+=1)0>o+f||o+f>=t||(0!=u||0!=f)&&a==r.isDark(n+u,o+f)&&(i+=1);i>5&&(e+=3+i-5)}for(var n=0;t-1>n;n+=1)for(var o=0;t-1>o;o+=1){var

c=0;r.isDark(n,o)&&(c+=1),r.isDark(n+1,o)&&(c+=1),r.isDark(n,o+1)&&(c+=1),r.isDark(n+1,o+1)&&(c+=1),(0==c||4==c)&&(e+=3)}

for(var n=0;t>n;n+=1)for(var

o=0;t-6>o;o+=1)r.isDark(n,o)&&!r.isDark(n,o+1)&&r.isDark(n,o+2)&&r.isDark(n,o+3)&&r.isDark(n,o+4)&&!r.isDark(n,o+5)&&r.isDark(n,o+6)&&(e+=40);

for(var o=0;t>o;o+=1)for(var

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