http://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=14&page=show_problem&problem=1229

Problem F

Coupons

Input: standard input

Output: standard output

Time Limit: 2 seconds

Memory Limit: 32 MB

 

Coupons in cereal boxes are numbered 1 to n, and a set of one of each is required for a prize (a cereal box, of course). With one coupon per box, how many boxes on average are required to make a complete set of n coupons?

Input

Input consists of a sequence of lines each containing a single positive integer n, 1<=n<=33, giving the size of the set of coupons. Input is terminated by end of file.

Output

For each input line, output the average number of boxes required to collect the complete set of n coupons. If the answer is an integer number, output the number. If the answer is not integer, then output the integer part of the answer followed by a space and then by the proper fraction in the format shown below. The fractional part should be irreducible. There should be no trailing spaces in any line of output.

Sample Input

2
5
17

Sample Output

3 
   5
11 --
   12
   340463
58 ------
   720720

(Math Lovers’ Contest, Source: University of Alberta Local Contest)

 

#include <cstdio>
#include <cstring>
#include <iostream>
#include <algorithm>
using namespace std;
#define ll long long
ll a , s , m , n;
ll gcd(ll a,ll b) {
    if(a == 0) return b;
    return gcd(b % a , a);
}
int wei(ll a) {
    int aa = 0;
    while(a) {
        aa ++;
        a /= 10;
    }
    return aa;
}
int main() {
    while(cin >> n) {
        a = 0;
        s = m = 1;
        for(ll i=2;i<=n;i++) {
            s = s * i + m;
            m *= i;
            ll t = gcd(s , m);
            s /= t;
            m /= t;
        }
        ll t = gcd(n , m);
        n /= t; m /= t;
        s *= n;
        a = s / m;
        s %= m;
        if(s == 0) {
            cout << a << endl;
            continue;
        }
        int wa = wei(a) , ws = wei(s) , wm = wei(m);
        for(int i=0;i<=wa;i++) printf(" "); cout << s << endl;
        cout << a; printf(" ");
        for(int i=0;i<wm;i++) printf("-"); puts("");
        for(int i=0;i<=wa;i++) printf(" "); cout << m << endl;
    }
    return 0;
}

  

 posted on 2013-08-10 11:16  tobec  阅读(762)  评论(0编辑  收藏  举报