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JSONArray数据转换成java List

package no.integrasco.ingentia.news.qaedition;

public class Person {

    private String name;

    private int age;

    public String getName() {

        return name;
    }

    public void setName(String name) {

        this.name = name;
    }

    public int getAge() {

        return age;
    }

    public void setAge(int age) {

        this.age = age;
    }
}

 

package no.integrasco.ingentia.news.qaedition;

import java.util.List;

import net.sf.json.JSONArray;
import net.sf.json.JsonConfig;

public class JsonTest {

    /**
     * @param args
     */
    public static void main(String[] args) {

        // 转换方法1
        JSONArray array = JSONArray.fromObject("[{'name':'hehe','age':22}]");
        List<Person> list = JSONArray.toList(array, Person.class);// 过时方法
        System.out.println(list.get(0).getName());

        // 转换方法2
        List<?> list2 = JSONArray.toList(array, new Person(), new JsonConfig());//参数1为要转换的JSONArray数据,参数2为要转换的目标数据,即List盛装的数据
        Person person = (Person) list2.get(0);
        System.out.println(person.getAge());
    }

}

 

从页面接收json格式的数据,在java类里面进行解析

String jsonStr = {"name":"zfj","dd":[{"ddr":"1","encrypt":"2","ff":"1","length":"23","ffe":"editStyled","ill":"1","pkor":"2","name":"zfj","isKey":"2","alias":"ffff"}],"addRelations":[{"type":"2","ld":"zfj","ld":"2"}]}; 

将此字符串放在ruquest或者其他的变量里面,传递到后台。 

如放在reques中: 
request.getRequestDispatcher("/geServlet?data="+jsonStr).forward(request,response); 

在servlet或java类里这样接收: 
String json = request.ge[size=large][/size]tParameter("data"); 
JSONObject jsonObject = JSONObject.fromObject(data); 
String name = jsonObject.getString(“name”); 
...... 
//对于数组这样接收用 

JSONArray jan = (JSONArray) jsonObject.get("dd"); 
if(jan!=null||jan.size()!=0){ 
for(int i=0;i<ja.size();i++){ 
JSONObject jo = JSONObject.fromObject(ja.get(i)); 
String ff = jo.getString("ff"); 
                 ...... 

posted on 2017-04-21 15:57  nickTimer  阅读(327)  评论(0编辑  收藏  举报