Golang等待一组协程结束

1. 利用waitgroup 

?

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17

import (     "log"     "sync"     "sync/atomic"     "time" ) func main() {     wg := sync.WaitGroup{}     for i := 0; i < 10; i++ {         wg.Add(1)         go func(i int) {             log.Println(i)             wg.Done()         }(i)     }     wg.Wait() }

2. 利用缓冲channel

?

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19

import (     "log"     "time" )   func main() {     ch := make(chan struct{}, 10)     var i int     for i = 0; i < 10; i++ {         go func(i int) {             log.Println(i)             ch <- struct{}{}         }(i)     }       for j := i; j > 0; j-- {         <-ch     } }

3. 利用非缓冲channel

?

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17

package main   import (    "log"    "time" )   func main() {    ch := make(chan struct{})    for i := 0; i < 10; i++ {       go func(i int) {          log.Println(i)          ch <- struct{}{}       }(i)       <-ch    } }

　　

4. 利用原子计数器

?

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21

package main   import (    "log"    "time"    "sync"    "sync/atomic" )   func main() {    var total int32    for  i := 0; i < 10; i++ {       go func(i int) {          log.Println(i)          atomic.AddInt32(&total,1)       }(i)    }    for atomic.LoadInt32(&total) < 10 {       time.Sleep(time.Microsecond)    } }