struts2、jsp的简单路径的简单拦截
<filter> <filter-name>UsersFilter</filter-name> <filter-class>com.web.UsersFilter</filter-class> </filter> <filter-mapping> <filter-name>UsersFilter</filter-name> <url-pattern>/*</url-pattern> </filter-mapping>
package com.web; import java.io.IOException; import javax.servlet.Filter; import javax.servlet.FilterChain; import javax.servlet.FilterConfig; import javax.servlet.ServletException; import javax.servlet.ServletRequest; import javax.servlet.ServletResponse; import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpServletResponse; import javax.servlet.http.HttpSession; public class UsersFilter implements Filter { public void doFilter(ServletRequest request, ServletResponse response, FilterChain chain) throws IOException, ServletException { // 设置请求的字符编码 request.setCharacterEncoding("UTF-8"); // 设置返回请求的字符编码 response.setCharacterEncoding("UTF-8"); // 转换ServletRequest为 HttpServletRequest HttpServletRequest req = (HttpServletRequest) request; // 转换ServletResponse为HttpServletRequest HttpServletResponse res = (HttpServletResponse) response; // 获取Session HttpSession session = req.getSession(); // 获取Session中存储的对象 Object o = session.getAttribute("user"); // 获取当前请求的URI String url = req.getRequestURI(); // 判断Session中的对象是否为空;判断请求的URI是否为不允许过滤的URI if (o==null && url.indexOf("test.jsp")<0 && url.indexOf("comment.jsp")<0 && url.indexOf("link.jsp")<0) { chain.doFilter(request, response); res.setHeader("Cache-Control","no-store"); res.setDateHeader("Expires",0); res.setHeader("Pragma","no-cache"); res.flushBuffer(); } } public void destroy() { // TODO Auto-generated method stub } public void init(FilterConfig arg0) throws ServletException { // TODO Auto-generated method stub } }
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作者:Honey_Badger —— 觉得这文章好,点一下左下角
出处:http://tk55.cnblogs.com/
posted on 2016-11-06 02:28 Honey_Badger 阅读(1223) 评论(0) 编辑 收藏 举报