思路:辅助字典,若存在,则返回字典中相应键对应的值。若不存在,返回0。
Python:
class Solution: def search(self, nums: List[int], target: int) -> int: from collections import Counter help_dict=Counter(nums) if target in help_dict: return help_dict[target] else: return 0
class Solution: def search(self, nums: List[int], target: int) -> int: from collections import Counter help_dict=Counter(nums) if target in help_dict: return help_dict[target] else: return 0