做题记录--day41

《算法笔记》3.4小节——入门模拟->日期处理

D无难度，注意格式是yyyy-mm-dd,年也是要补足的，样例里面没有提醒但是自己要注意啊！！

#include<stdio.h>
int month[13][2]={0,0,31,31,28,29,31,31,30,30,31,31,30,30,31,31,31,31,30,30,31,31,30,30,31,31};
bool isrun(int year)
{
    if((year%4==0 && year%100!=0) || year%400==0)
        return true;
    return false;
}
int main()
{
    int y,n;
    while(scanf("%d %d",&y,&n)!=EOF)
    {
        int i=1;
        while(n-month[i][isrun(y)]>0)
        {
            n=n-month[i][isrun(y)];
            i++;
            if(i==13)
            {
                i=1;
                y++;
            }
        }
        printf("%04d-%02d-%02d\n",y,i,n);
    }
    return 0;
}

 E没啥难度，注意跟前面的A区分，这里面两天的差值，相隔一天是一天，A题中相邻两天是两天

这里面从去年到今年的同一天（今年当天不算），对应闰年是365，对应平年364

#include<stdio.h>
int month[13][2]={0,0,31,31,28,29,31,31,30,30,31,31,30,30,31,31,31,31,30,30,31,31,30,30,31,31};
bool isrun(int year)
{
    if((year%4==0 && year%100!=0) || year%400==0)
        return true;
    return false;
}
int main()
{
    int n;
    scanf("%d",&n);
    while(n--)
    {
        int y,m,d,sum;
        scanf("%d %d %d %d",&y,&m,&d,&sum);
        int data=m*100+d;
        while(sum>=365)
        {
            if(data<=229)
            {
                if(isrun(y))
                {
                    sum=sum-365;
                    //y++;
                    if(data==229)
                    {
                        data=301;
                        m=3;
                        d=1;
                    }
                }
                else
                    sum=sum-364;
                y++;
            }
            else
            {
                if(isrun(y+1))
                {
                    sum=sum-365;
                }
                else
                    sum=sum-364;
                y++;
            }
        }
        while(sum>0)
        {
            d++;
            sum--;
            if(d>month[m][isrun(y)])
            {
                d=1;
                m++;
                if(m>12)
                {
                    m=1;
                    y++;
                }
            }
        }
        printf("%04d-%02d-%02d\n",y,m,d);
    }
    return 0;
}