序列

序列是具有先后关系的一组元素

 

 

 

 s[0]:第0个位置

 

>>> s ='123456'
>>> s[0:2]
'12'
>>> s[::2]
'135'
>>> s*3
'123456123456123456'
>>> t='cv'
>>> s+t
'123456cv'
>>> '1' in s
True

>>> A =[1 ,2, 3]
>>> A
[1, 2, 3]
>>> A=A[:2]
>>> A
[1, 2]
>>> A[1]
2

 

列表

 

 

 

xs = [1,2,3]
print(xs,xs[2])
print(xs[-1])
xs[2]='too'
print(xs)
xs.append('good')
print(xs)
x = xs.pop()
print(x,xs)

[1, 2, 3] 3
3
[1, 2, 'too']
[1, 2, 'too', 'good']
good [1, 2, 'too']

>>> ls = ['ac','da','dvv']
>>> la.append('sf')
Traceback (most recent call last):
  File "<pyshell#93>", line 1, in <module>
    la.append('sf')
NameError: name 'la' is not defined
>>> ls.append('acd')
>>> ls
['ac', 'da', 'dvv', 'acd']
>>> ls.insert(0,'dvs')
>>> ls
['dvs', 'ac', 'da', 'dvv', 'acd']
>>> a = ls.pop(1)
>>> a
'ac'
>>> ls
['dvs', 'da', 'dvv', 'acd']
>>> ls = ['a','a','c','d','c']
>>> ls.remove('a')
>>> ls
['a', 'c', 'd', 'c']
>>> ls.remove('c')
>>> ls
['a', 'd', 'c']
>>> ls.reverse()
>>> ls
['c', 'd', 'a']

 

 

 

 

 del ls[i:j:k] [i:j] 左闭右开

>>> ls[0:3:2]=['96','36']
>>> ls
['96', 'waf', '36', 'vgf']
>>> del ls[0]
>>> ls
['waf', '36', 'vgf']
>>> del ls[0:3:2]
>>> ls
['36']
>>>  ls+=['afv','d','vs']
SyntaxError: unexpected indent
>>> ls+=['afv','d','vs']
>>> ls
['36', 'afv', 'd', 'vs']
>>> ls*=2
>>> ls
['36', 'afv', 'd', 'vs', '36', 'afv', 'd', 'vs']

 Slicing:

 

 

>>> s = ['dcv','vfs','123']
>>> s[::-1]
['123', 'vfs', 'dcv']
>>> s='123466'
>>> len(s)
6
>>> min(s)
'1'
>>> max(s)
'6'
>>> s.index('6')
4
>>> s.index('6',0,3)
Traceback (most recent call last):
  File "<pyshell#64>", line 1, in <module>
    s.index('6',0,3)
ValueError: substring not found
>>> s.count('6')
2

 

 

 

元组

 

 >>> cre = 'a','b','c'
>>> cre
('a', 'b', 'c')
>>> cer = (cre,0x10,'red')
>>> cer
(('a', 'b', 'c'), 16, 'red')

>>> cer[0][1]
'b'

 

 

 

 

#获取多个输入的数字
def get():
    num= []
    isn  = input('请输入数字： ')
    while isn !='':
        num.append(eval(isn))
        isn  = input('请输入数字： ')
        #isn  = eval(input('请输入数字： '))是错的，不能eval(空)
    return num
print(get())