函数reduce,lambda,filter

#比较时间差，判断执行有时。

import time
def panduan(x):
    if x%5==0 and x%7==0:
        return True
    else:
        return  False
start_time=time.time()
print reduce((lambda x,y:x+y),filter(panduan,range(1001)))
end_time=time.time()
print end_time-start_time

sum=0
start_time1=time.time()
for i in range(1001):
    if i%5==0 and i%7==0:
        sum=sum+i
print sum
end_time1=time.time()
print end_time1-start_time1

#执行结果
#14210
#0.00799989700317
#14210
#0.00500011444092

两种方法执行1000以内即被5又被7整除的数的和，比较执行所需时间