XPath 获取两个node中间的HTML Nodes
//div[@id="Recipe"]//h5[contains(text(),"Ingredients")]/following-sibling::p[count(.|//div[@id="Recipe"]//h5[contains(text(),"Method")]/preceding-sibling::p) = count(//div[@id="Recipe"]//h5[contains(text(),"Method")]/preceding-sibling::p)]
In XPath 1.0 one way to do this is by using the Kayessian method for node-set intersection:
$ns1[count(.|$ns2) = count($ns2)]The above expression selects exactly the nodes that are part both of the node-set $ns1 and the node-set $ns2.
To apply this to the specific question -- let's say we need to select all nodes between the 2nd and 3rd h3 element in the following XML document:
<html>
<h3>Title T31</h3>
<a31/>
<b31/>
<h3>Title T32</h3>
<a32/>
<b32/>
<h3>Title T33</h3>
<a33/>
<b33/>
<h3>Title T34</h3>
<a34/>
<b34/>
<h3>Title T35</h3>
</html>We have to substitute $ns1 with:
/*/h3[2]/following-sibling::node()and to substitute $ns2 with:
/*/h3[3]/preceding-sibling::node()Thus, the complete XPath expression is:
/*/h3[2]/following-sibling::node()
[count(.|/*/h3[3]/preceding-sibling::node())
=
count(/*/h3[3]/preceding-sibling::node())
]We can verify that this is the correct XPath expression:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:template match="/">
<xsl:copy-of select=
"/*/h3[2]/following-sibling::node()
[count(.|/*/h3[3]/preceding-sibling::node())
=
count(/*/h3[3]/preceding-sibling::node())
]
"/>
</xsl:template>
</xsl:stylesheet>When this transformation is applied on the XML document presented above, the wanted, correct result is produced:
<a32/>
<b32/>II. XPath 2.0 solution:
Use the intersect operator:
/*/h3[2]/following-sibling::node()
intersect
/*/h3[3]/preceding-sibling::node()
