37. 解数独
编写一个程序,通过填充空格来解决数独问题。
数独的解法需 遵循如下规则:
数字 1-9 在每一行只能出现一次。
数字 1-9 在每一列只能出现一次。
数字 1-9 在每一个以粗实线分隔的 3x3 宫内只能出现一次。(请参考示例图)
数独部分空格内已填入了数字,空白格用 '.' 表示。
来源:力扣(LeetCode)
链接:https://leetcode-cn.com/problems/sudoku-solver
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回溯
import java.util.ArrayList;
import java.util.List;
class Solution {
private char[][] board;
private boolean[][] row = new boolean[9][9];
private boolean[][] col = new boolean[9][9];
private boolean[][][] block = new boolean[3][3][9];
private List<int[]> spaces = new ArrayList<>();
private boolean valid = false;
private void solve(int index) {
if (index == spaces.size()) {
valid = true;
return;
}
int[] space = spaces.get(index);
for (int digit = 0; digit < 9 && !valid; digit++) {
if (!row[space[0]][digit] && !col[space[1]][digit] && !block[space[0] / 3][space[1] / 3][digit]) {
row[space[0]][digit] = col[space[1]][digit] = block[space[0] / 3][space[1] / 3][digit] = true;
board[space[0]][space[1]] = (char) (digit + '0' + 1);
solve(index + 1);
row[space[0]][digit] = col[space[1]][digit] = block[space[0] / 3][space[1] / 3][digit] = false;
}
}
}
public void solveSudoku(char[][] board) {
if (board == null || board.length == 0 || board[0].length == 0) {
return;
}
this.board = board;
for (int i = 0; i < 9; ++i) {
for (int j = 0; j < 9; ++j) {
if (board[i][j] == '.') {
spaces.add(new int[]{i, j});
} else {
int digit = board[i][j] - '0' - 1;
row[i][digit] = col[j][digit] = block[i / 3][j / 3][digit] = true;
}
}
}
solve(0);
}
}
位运算优化
import java.util.ArrayList;
import java.util.List;
class Solution {
private int[] line = new int[9];
private int[] column = new int[9];
private int[][] block = new int[3][3];
private boolean valid = false;
private List<int[]> spaces = new ArrayList<int[]>();
public void solveSudoku(char[][] board) {
for (int i = 0; i < 9; ++i) {
for (int j = 0; j < 9; ++j) {
if (board[i][j] == '.') {
spaces.add(new int[]{i, j});
} else {
int digit = board[i][j] - '0' - 1;
flip(i, j, digit);
}
}
}
dfs(board, 0);
}
public void dfs(char[][] board, int pos) {
if (pos == spaces.size()) {
valid = true;
return;
}
int[] space = spaces.get(pos);
int i = space[0], j = space[1];
int mask = ~(line[i] | column[j] | block[i / 3][j / 3]) & 0x1ff;
for (; mask != 0 && !valid; mask &= (mask - 1)) {
int digitMask = mask & (-mask);
int digit = Integer.bitCount(digitMask - 1);
flip(i, j, digit);
board[i][j] = (char) (digit + '0' + 1);
dfs(board, pos + 1);
flip(i, j, digit);
}
}
public void flip(int i, int j, int digit) {
line[i] ^= (1 << digit);
column[j] ^= (1 << digit);
block[i / 3][j / 3] ^= (1 << digit);
}
}
枚举优化
import java.util.ArrayList;
import java.util.List;
class Solution {
private int[] line = new int[9];
private int[] column = new int[9];
private int[][] block = new int[3][3];
private boolean valid = false;
private List<int[]> spaces = new ArrayList<int[]>();
public void solveSudoku(char[][] board) {
for (int i = 0; i < 9; ++i) {
for (int j = 0; j < 9; ++j) {
if (board[i][j] != '.') {
int digit = board[i][j] - '0' - 1;
flip(i, j, digit);
}
}
}
while (true) {
boolean modified = false;
for (int i = 0; i < 9; ++i) {
for (int j = 0; j < 9; ++j) {
if (board[i][j] == '.') {
int mask = ~(line[i] | column[j] | block[i / 3][j / 3]) & 0x1ff;
if ((mask & (mask - 1)) == 0) {
int digit = Integer.bitCount(mask - 1);
flip(i, j, digit);
board[i][j] = (char) (digit + '0' + 1);
modified = true;
}
}
}
}
if (!modified) {
break;
}
}
for (int i = 0; i < 9; ++i) {
for (int j = 0; j < 9; ++j) {
if (board[i][j] == '.') {
spaces.add(new int[]{i, j});
}
}
}
dfs(board, 0);
}
public void dfs(char[][] board, int pos) {
if (pos == spaces.size()) {
valid = true;
return;
}
int[] space = spaces.get(pos);
int i = space[0], j = space[1];
int mask = ~(line[i] | column[j] | block[i / 3][j / 3]) & 0x1ff;
for (; mask != 0 && !valid; mask &= (mask - 1)) {
int digitMask = mask & (-mask);
int digit = Integer.bitCount(digitMask - 1);
flip(i, j, digit);
board[i][j] = (char) (digit + '0' + 1);
dfs(board, pos + 1);
flip(i, j, digit);
}
}
public void flip(int i, int j, int digit) {
line[i] ^= (1 << digit);
column[j] ^= (1 << digit);
block[i / 3][j / 3] ^= (1 << digit);
}
}
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