Project Euler Problem6

Sum square difference

Problem 6

The sum of the squares of the first ten natural numbers is,

12 + 22 + ... + 102 = 385

The square of the sum of the first ten natural numbers is,

(1 + 2 + ... + 10)2 = 552 = 3025

Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 − 385 = 2640.

Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.

 

Quite simple , the code is as follows:

def getSumOfSquare(began,end):
    sum = 0
    for i in range(began, end+1):
        sum += pow(i, 2)
    return sum

def getSquareOfSum(began, end):
    sum = 0
    for i in range(began, end+1):
        sum += i
    sum = pow(sum, 2)
    return sum

print(getSumOfSquare(1, 100))
print(getSquareOfSum(1, 100))
print(getSquareOfSum(1, 100)-getSumOfSquare(1, 100))

　　

posted @ 2013-12-12 18:29  tianxiaozz  阅读(181)  评论(0)  编辑  收藏  举报