06 2013 档案
摘要：更好的遍历Josn的方法，利用jquery的each方法： var arr1 = [ "one", "two", "three", "four", "five" ]; $.each(arr1, function(){ alert(this); }); 输出：one two three four five var arr2 = [[1, 2, 3], [4, 5, 6], [7, 8, 9]] $.each(arr2, function(i, item){ alert(item[0]); });
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