ぷ行走de猫げ

在快乐中成长,在快乐中学习!

摘要: string arr = "['one','two','three','four']";List<string> arrlist = JsonConvert.DeserializeObject<List<string>>(arr);string arr = "{[a:'one'],[b:'two'],[c:'three'],[d:'four']}";List<user> arrli 阅读全文
posted @ 2012-06-13 13:03 李天翔 阅读(1473) 评论(1) 推荐(0) 编辑