Java CompletableFuture.allOf() 找不到任何数组元素
一个非常简单的代码片段如下:
String[] list = {"a", "b", "c"};
List<CompletableFuture<String>> completableFutureList = new ArrayList<>();
for (String s : list) {
completableFutureList.add(CompletableFuture.supplyAsync(() -> s)
.thenApply(String::toUpperCase));
}
CompletableFuture<String>[] a = completableFutureList
.toArray(new CompletableFuture[completableFutureList.size()]);
System.out.println(a.length);
CompletableFuture.allOf(a).whenComplete((r, e) -> {
if (null != r) {
System.out.println(r);
} else {
throw new RuntimeException(e);
}
});
我希望程序应该打印“A B C”。但实际上没有打印任何内容。为什么以及如何解决这个问题?
最佳答案
引用 CompletableFuture.allOf()
的 Javadoc方法(强调我的):
Returns a new
CompletableFuture
that is completed when all of the givenCompletableFutures
complete. If any of the givenCompletableFutures
complete exceptionally, then the returnedCompletableFuture
also does so, with aCompletionException
holding this exception as its cause. Otherwise, the results, if any, of the givenCompletableFutures
are not reflected in the returnedCompletableFuture
, but may be obtained by inspecting them individually. If noCompletableFutures
are provided, returns aCompletableFuture
completed with the value {@code null}.
所以我认为您需要在
a[0].get()
中手动查询它们(例如使用 whenComplete()
)。打回来。像这样的东西:CompletableFuture.allOf(a).whenComplete((r, e) -> {
for (CompletableFuture<String> future : a) {
try {
System.out.println(future.get());
}
catch (InterruptedException | ExecutionException e1) {
e1.printStackTrace();
}
}
});
关于Java CompletableFuture.allOf() 找不到任何数组元素,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/54365047/