bzoj3595[Scoi2014]方伯伯的OJ

题目链接
直接动态开点线段树,维护所有可能出现的位置\([-m,n+m]\),并按排名排列元素,记个区间元素个数以及底层节点代表的编号,再搞个map记每个编号对应在线段树中出现的位置即可,跑的飞快,远超平衡树。

#include<cstdio>
#include<cstdlib>
#include<cstring>
#include<iostream>
#include<vector>
#include<algorithm>
#include<cmath>
#include<map>
#define P puts("lala")
#define cp cerr<<"lala"<<endl
#define ln putchar('\n')
#define pb push_back
#define fi first
#define se second
#define mkp make_pair
using namespace std;
inline int read()
{
    char ch=getchar();int g=1,re=0;
    while(ch<'0'||ch>'9') {if(ch=='-')g=-1;ch=getchar();}
    while(ch<='9'&&ch>='0') re=(re<<1)+(re<<3)+(ch^48),ch=getchar();
    return re*g;
}
typedef long long ll;
typedef double db;
typedef pair<int,int> pii;

map<int,int>mp;
int n,m;
const int N=100050;
int key[N*60],ch[N*60][2],sum[N*60],rt,sz=0,L,R;
int updateid(int &o,int l,int r,int x,int k)
{
    if(!o) 
    {
        o=++sz;sum[o]=max(min(r,n)-max(l,1)+1,0);
        if(l==r) key[o]=l;
    }
    if(l==r) {key[o]=k; return 0;}
    int mid=l+r>>1,lsiz=ch[o][0]?sum[ch[o][0]]:max(min(mid,n)-max(l,1)+1,0);
    if(x<=mid) return updateid(ch[o][0],l,mid,x,k);
    else return updateid(ch[o][1],mid+1,r,x,k)+lsiz;
}
int update(int &o,int l,int r,int x,int k,int id)
{
    if(!o) 
    {
        o=++sz;sum[o]=max(min(r,n)-max(l,1)+1,0);
        if(l==r) key[o]=l;
    }
    sum[o]+=k;
    if(l==r) {if(id!=-1) key[o]=id;return 0;}
    int mid=l+r>>1,lsiz=ch[o][0]?sum[ch[o][0]]:max(min(mid,n)-max(l,1)+1,0);
    if(x<=mid) return update(ch[o][0],l,mid,x,k,id);
    else return update(ch[o][1],mid+1,r,x,k,id)+lsiz;
}
int query(int &o,int l,int r,int k)
{
    if(!o) 
    {
        o=++sz;sum[o]=max(min(r,n)-max(l,1)+1,0);
        if(l==r) key[o]=l;
    }
    if(l==r) return key[o];
    int mid=l+r>>1,lsiz=ch[o][0]?sum[ch[o][0]]:max(min(mid,n)-max(l,1)+1,0);
    if(k<=lsiz) return query(ch[o][0],l,mid,k);
    else return query(ch[o][1],mid+1,r,k-lsiz);
}

int main()
{
#ifndef ONLINE_JUDGE
    freopen("1.in","r",stdin);freopen("1.out","w",stdout);
#endif
    int i,j,opt,T;
    n=read(); m=read();
    L=1; R=n;
    int lastans=0;
    for(int cas=1;cas<=m;++cas)
    {
        opt=read();
        if(opt==1) //modify id
        {
            int x=read(),y=read(); x-=lastans; y-=lastans;
            if(!mp.count(x)) mp[x]=x;
            mp[y]=mp[x]; mp.erase(x);
            printf("%d\n",lastans=updateid(rt,-m,n+m,mp[y],y)+1);
        }
        else if(opt==2) //make it first
        {
            int x=read(); x-=lastans;
            if(!mp.count(x)) mp[x]=x;
            printf("%d\n",lastans=update(rt,-m,m+n,mp[x],-1,-1)+1);
            L--; mp[x]=L;
            update(rt,-m,n+m,L,1,x);
        }
        else if(opt==3) //make it last
        {
            int x=read(); x-=lastans;
            if(!mp.count(x)) mp[x]=x;
            printf("%d\n",lastans=update(rt,-m,n+m,mp[x],-1,-1)+1);
            R++; mp[x]=R;
            update(rt,-m,n+m,R,1,x);
        }
        else if(opt==4) //query kth's id
        {
            int k=read(); k-=lastans;
            printf("%d\n",lastans=query(rt,-m,n+m,k));
        }
    }
    return 0;
}
posted @ 2018-01-11 20:59  BLMontgomery  阅读(196)  评论(0编辑  收藏  举报