sicp每日一题[1.42]

Exercise 1.42

Let f and g be two one-argument functions. The composition f after g is defined to be the function x->f(g(x)). Define a procedure compose that implements composition. For example, if inc is a procedure that adds 1 to its argument,

 ((compose square inc) 6)
 49

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这道题也非常简单，跟上一题几乎一模一样，只是把 double 换成一个通用的单参数函数而已。

(define (compose f g)
  (lambda (x) (f (g x))))


((compose square inc) 6)
((compose inc square) 6)

; 执行结果
49
37