python查找替换危险字符脚本

为了哥们儿的大创写了这么个脚本

代码如下：

import io
import base64

def replace_dangerous_sequences(image_path):
    try:
        # 读取图像文件的内容
        with open(image_path, 'rb') as image_file:
            image_data = image_file.read()

        # 定义危险字节序列的列表和替换为的空字节串
        # 格式为 b'要查杀的字符'
        dangerous_sequences = [b'<?php', b'?>', b'os']
        replace_with = b''

        # 检查图像数据中是否包含危险字节序列
        found_dangerous_sequences = []
        for seq in dangerous_sequences:
            if seq in image_data:
                found_dangerous_sequences.append(seq)

        # 如果发现危险字节序列，打印出来
        find = 0
        if found_dangerous_sequences:
            print("发现危险字节序列:")
            for seq in found_dangerous_sequences:
                print(seq)
            find = 1
        else:
            print("未发现危险字节序列")

        # 替换图像数据中的危险字节序列为空字节串
        if find == 1:
            for seq in dangerous_sequences:
                image_data = image_data.replace(seq, replace_with)

            # 将替换后的数据保存到新的文件
            with open(image_path, 'wb') as image_file:
                image_file.write(image_data)
            print("危险字节序列已替换并保存到", image_path)
    except Exception as e:
        print("发生错误:", str(e))

# 调用函数并传递图像文件路径作为参数
replace_dangerous_sequences("2.png")

需求有点难以理解，真要防护为啥不直接上传就直接查杀呢