java消除整型数组中重复的元素，排序后输出新数组

法一：

import java.util.Arrays;
import java.util.Scanner;

public class Main
{
	public static void main(String[] args)
	{
		int[] a = new int[50];
		Scanner scanner = new Scanner(System.in);
		int index = 0;
		String x;
		while(!(x=scanner.nextLine()).equals(""))
		{
			a[index++] = Integer.parseInt(x);
		}
		Arrays.sort(a,0,index);
		int k = 0;
		for(int i = 0;i<index;i++)
		{
			if(a[k]!=a[i]) {
				a[++k] = a[i];
			}
		}
		for(int i = 0;i<k+1;i++)
		{
			System.out.print(a[i]+" ");
		}
		scanner.close();
	}
}

输入输出如下：

1
2
2
4
5
4
3

1 2 3 4 5 

法二： 

使用集合（自动排序去重）

import java.util.HashSet;
import java.util.Scanner;
import java.util.Set;

public class Main
{
	public static void main(String[] args)
	{
		Scanner scanner = new Scanner(System.in);
		String x;
		Set<String> set = new HashSet<String>(); 
		while(!(x=scanner.nextLine()).equals(""))
		{
			set.add(x);
		}
		String[] a = new String[set.size()];
		set.toArray(a);
		for(int i = 0;i<a.length;i++)
		{
			System.out.print(a[i]+" ");
		}
		scanner.close();
	}
}

输入输出如下： 

1
2
3
2
4
2
3
5

1 2 3 4 5