已知一个日期和天数， 求多少天后的日期（是那个超时代码的AC版) 

  1 #include <stdio.h>
  2 #include <string.h>
  3 int m2 = 29;
  4 int judge_year(int x)
  5 {
  6 
  7         if(x % 400 == 0 || x % 4 == 0 && x % 100 != 0)
  8             return 1;
  9         else
 10             return 0;
 11 
 12 }
 13 
 14 //extern int m2;
 15 int calculate_year(int *x, int y)
 16 {
 17         
 18         //extern int m2 = ;//出现 cannot initialize extern variables with block scope错误，即不能在块作用域里声明全局变量
 19 
 20         int span = 366;        
 21         while(*x - span >= 0){
 22                 
 23                 y++;/*天数满一年加1*/
 24                 *x -= span;/*减去今年的天数*/
 25                 span = judge_year(y) ? 366 : 365;/*判断下一年的天数*/
 26                 
 27         }
 28         m2 = judge_year(y) ? 29 : 28;/*判断几天后2月份的天数*/
 29         return y;
 30 
 31 }
 32 //extern int m2;
 33 int calculate_month(int *x, int m)
 34 {
 35 
 36         int span = 31;
 37         while(*x - span >= 0){
 38 
 39                 m++;
 40                 *x -= span;
 41                 if(m == 1 || m == 3 || m == 5 || m == 7 || m == 8 || m == 10 || m == 12)
 42                 {
 43 
 44                         span = 31;
 45 
 46                 }
 47                 else if(m == 4 || m == 6 || m == 9 || m == 11)
 48                 {
 49 
 50                         span = 30;
 51 
 52                 }
 53                 else
 54                 {
 55                     
 56                         span = m2;
 57 
 58                 }
 59 
 60         }
 61         return m;
 62                 
 63 }
 64 
 65 extern int m2;
 66 int main()
 67 {
 68     
 69         int year = 2000, month = 1, day = 1, L_year, L_month, sum, X_sum;
 70         char s[10];
 71         //int m2=29;
 72         while(scanf("%d", &sum) && sum != -1){
 73 
 74                 day = 1;
 75                 X_sum = sum;
 76                 L_year = calculate_year(&sum, year);
 77                 L_month = calculate_month(&sum, month);
 78                 day += sum;
 79                 switch(X_sum % 7)
 80                 {
 81 
 82                         case 6: strcpy(s, "Friday"); break;
 83                         case 0: strcpy(s, "Saturday"); break;
 84                         case 1: strcpy(s, "Sunday"); break;
 85                         case 2: strcpy(s, "Monday"); break;
 86                         case 3: strcpy(s, "Tuesday"); break;
 87                         case 4: strcpy(s, "Wednesday"); break;
 88                         case 5: strcpy(s, "Thursday"); 
 89 
 90                  }                       
 91                 printf("%d-", L_year);
 92                 if(L_month <= 9)
 93                     printf("0%d-", L_month);
 94                 else
 95                     printf("%d-", L_month);
 96                 if(day <= 9)
 97                     printf("0%d ", day);
 98                 else
 99                     printf("%d ", day);
100                 printf("%s\n", s);
101             //    printf("%d %d %d\n", L_year, m2, L_month);
102 
103         }
104         return 0;
105 
106 }
View Code

 

一个学姐路过，看到我的代码，认为没有那么麻烦，于是自己写了一个，

 1 #include <stdio.h>
 2 #include <string.h>
 3 int judge_year(int x)
 4 {
 5 
 6         if(x % 400 == 0 || x % 4 == 0 && x % 100 != 0)
 7             return 1;
 8         else
 9             return 0;
10 
11 }
12 int main()
13 {
14     int year = 2000, month = 1, day = 1,sum,week,i;
15     int ans[12]={31,28,31,30,31,30,31,31,30,31,30,31},a[2]={365,366};
16     char s[7][10]={"Saturday","Sunday","Monday","Tuesday","Wednesday","Thursday","Friday"};
17     while(scanf("%d", &sum) && sum != -1)
18     {
19         week=sum%7;
20         year = 2000, month = 1, day = 1;
21         while(sum>=a[judge_year(year)])
22         {
23             sum-=a[judge_year(year)];
24             year++;
25         }
26         if(judge_year(year))
27             ans[1]=29;
28         else
29             ans[1]=28;
30         for(i=0;i<12;i++)
31         {
32             if(sum>=ans[i])
33             {
34                 sum-=ans[i];
35                 month++;
36             }
37             else
38                 break;
39         }
40         day+=sum;
41         printf("%4d-%02d-%02d %s\n",year,month,day,s[week]);
42     }
43     return 0;
44 }
View Code


跟我的执行时间等等一样，但长度明显短了许多。

 

posted @ 2013-08-02 15:11  心中的阿哲  阅读(528)  评论(0)  编辑  收藏  举报