ElasticSearch返回不同的type的序列化
总体思路是:
利用json序列化的别名方法,反序列化到不同的字段上;
因为别名方法不支持多个别名,所以不得不根据不同的type,定义了多套适配内容。
最终在属性上进行选择。
本示例ElasticSearch返回的json串形如:
{ "took": 4, "timed_out": false, "_shards": { "total": 5, "successful": 5, "failed": 0 }, "hits": { "total": 2, "max_score": 3.4698925, "hits": [ { "_index": "user", "_type": "userinfo", "_id": "1031014642252640", "_score": 3.4698925, "_source": { "uid": 1031014642252640, "level": 20 } } , { "_index": "user", "_type": "good", "_id": "1", "_score": 0.06378032, "_source": { "id": 1, "name": "good luck" } } ] } }
using PlainElastic.Net; using PlainElastic.Net.Queries; using PlainElastic.Net.Serialization; using System; using System.Collections.Generic; using Newtonsoft.Json; namespace TestQuery { [Serializable] public class Show { /* A实体反序列化内容 */ [JsonProperty(PropertyName = "uid")] private string title_1; [JsonProperty(PropertyName = "level")] private string content_1; /* B实体反序列化内容 */ [JsonProperty(PropertyName = "id")] private string title_2; [JsonProperty(PropertyName = "name")] private string content_2; /* AB实体反序列化内容汇总返回 */ public string Title { get { return title_1 ?? title_2; } } public string Content { get { return content_1 ?? content_2; } } } class Program { static void Main(string[] args) { var query = new QueryBuilder<Object>() .Query(q => q.Bool(b => b.Should(m => m.Term(tm => { tm.Field("uid"); tm.Value("1031014642252640"); return tm; }).Custom(@"{ ""exists"": { ""field"": ""name"" } }") ) ) ) .From(0) .Size(100) //.Sort(s => s.Field(UserInfoField.level, SortDirection.desc)) .BuildBeautified(); Console.WriteLine(query); List<Show> list = new List<Show>(); var cmd = new SearchCommand("user"); var client = new ElasticConnection("localhost", 9200); var operationResult = client.Post(cmd, query); var serializer = new JsonNetSerializer(); var hits = serializer.ToSearchResult<Show>(operationResult).hits; var serializerResult = hits.hits; //页面显示实体 // foreach (var item in serializerResult) { list.Add(item._source); } } } }
posted on 2016-05-31 14:33 Anthony.Zhao 阅读(1209) 评论(0) 编辑 收藏 举报