摘要:
class Solution {public: double pow(double x, int n) { double a=1; if(n==0)return 1; if(x==1)return 1; if(x==-1) { if(n&1)return -1; else return 1; } int absn=abs(n); a=power(x,absn); if(n>1); r... 阅读全文
摘要:
dfsclass Solution {public:string str[8]={"abc","def","ghi","jkl","mno","pqrs","tuv","wxyz"};vectors; vector letterCombinations(string digits) { s.clear(); dfs(digits,""); return s; } void dfs(string digits,stri 阅读全文