摘要: 组合:#include "stdafx.h"#include<iostream>using namespace std;void print(int n,int *A,int cur,int *B){ if(cur==n) { for(int i=0;i<cur;i++) { if(B[i]) { printf("%d",A[i]); } } printf("\n"); return; } B[cur]=1; print(n,A,cur+1,B); B[cur]=0; print(n,A,cur+1,B);}int 阅读全文
posted @ 2013-03-07 14:23 代码改变未来 阅读(155) 评论(0) 推荐(0) 编辑