题目

简单的八方向搜索，暴力即可


代码：

#include<cstdio>
#include<cstring>
#include<ctype.h>
#include<iostream>
using namespace std;
#define bug(s) cout<<#s<<"="<<s
#define stop {getchar();getchar();}

#define MAXN 52
#define MAXK 22

char a[MAXN][MAXN];
char words[MAXK][MAXN];
int n, m;
int k;

const int dx[] = { -1, 1, 0, 0, 1, -1, 1, -1 };
const int dy[] = { 0, 0, 1, -1, 1, -1, -1, 1};


int walk(int dir, int x, int y, int cur, char wd[], int num)
{
    if(cur == num) return 1;
    if(x<0 || x>=n) return 0;
    if(y<0 || y>=m) return 0;
    if(tolower(wd[cur]) == a[y][x])
    {
        return walk(dir, x+dx[dir], y+dy[dir], cur+1, wd, num);
    }
    else return 0;
}
void solve(int idx)   //idx in k words to search
{
    for(int i=0; i<m; i++)
        for(int j=0; j<n; j++)
        {
            for(int d=0; d<8; d++)
            {
                if(walk(d, j, i, 0, words[idx], strlen(words[idx])))
                {
                    printf("%d %d\n", i+1, j+1);
                    return;       //return写成break，wa一次。。
                }
            }
        }
}

int main()
{
    int t;
    scanf("%d", &t);
    while(t--)
    {
        scanf("%d%d", &m, &n);
        for(int i=0; i<m; i++)  //m lines
        {
            scanf("%s", a[i]);
            for(int j=0; j<n; j++)
                a[i][j] = tolower(a[i][j]);
        }
        scanf("%d", &k);
        for(int i=0; i<k; i++)
        {
            scanf("%s", words[i]);
        }
        for(int i=0; i<k; i++)
        {
            solve(i);
        }
        if(t) printf("\n");//The outputs of two consecutive cases will be separated by a blank line.
    }
}