摘要:
class Solution { public int[] printNumbers(int n) { int m = (int)Math.pow(10,n); int[] nums = new int[m-1]; for(int i = 1;i<m;i++){ nums[i-1] = i; } r 阅读全文
摘要:
class Solution { public double myPow(double x, int n) { if(x == 1) return 1; if(x == -1) return n%2==0?1:-1; if(n<-1000) return 0; if(n<0) return 1.0/ 阅读全文