第四章.编程练习
第一题
1 #include<iostream> 2 #include<string> 3 using namespace std; 4 int main() 5 { 6 char fristname[20]; 7 char lastname[20]; 8 char grade; 9 int age; 10 11 cout<<"what is your first name? "; 12 cin.getline(fristname,20); 13 cout<<"what is your last name ? "; 14 cin.getline(lastname,20); 15 cout<<"what letter grade do you deserve "; 16 cin>>grade; 17 cout<<"what is your age "; 18 cin>>age; 19 20 cout<<"name: "<<lastname<<" , "<<fristname<<endl; 21 cout<<"grade "<<char(grade+1)<<endl; 22 cout<<"age "<<age<<endl; 23 return 0; 24 }
第二题
1 #include<iostream> 2 #include<string> 3 using namespace std; 4 int main() 5 { 6 string name; 7 string dessert; 8 9 cout<<"enter your name "; 10 getline(cin,name);//c++中用getline输入string类的用法 11 cout<<"enter your favorite dessert "; 12 getline(cin,dessert); 13 cout<<"i have some delicous "<<dessert<<" for you "<<name<<endl; 14 return 0; 15 }
第三题
1 #include<iostream> 2 #include<cstring> 3 #include<string> 4 using namespace std; 5 int main() 6 { 7 char lastname[40],firstname[20]; 8 9 cout<<"enter your first name"; 10 cin.getline(firstname,20); 11 cout<<"enter your last name"; 12 cin.getline(lastname,20); 13 14 strcat(lastname,", "); 15 strcat(lastname,firstname); 16 17 cout<<"here is the information in a single string "<<lastname<<endl; 18 return 0; 19 }
第四题
1 #include<iostream> 2 #include<string> 3 using namespace std; 4 int main() 5 { 6 string firstname,lastname; 7 string name; 8 9 cout<<"enter your first name "; 10 cin>>firstname; 11 cout<<"enter your last name "; 12 cin>>lastname; 13 14 name=lastname+", "+firstname; 15 16 cout<<"here is the information in a single string: "<<name<<endl; 17 return 0; 18 }
第五题
1 #include<iostream> 2 #include<string> 3 using namespace std; 4 struct CandyBar 5 { 6 string kind; 7 float weight; 8 int cal; 9 }; 10 11 int main() 12 { 13 CandyBar snack={"mocha munch",2.3,250}; 14 cout<<snack.kind<<","<<snack.weight<<" ,"<<snack.cal<<endl; 15 return 0; 16 }
第六题
1 #include<iostream> 2 #include<string> 3 using namespace std; 4 struct CandyBar 5 { 6 string kind; 7 float weight; 8 int cal; 9 }; 10 11 int main() 12 { 13 CandyBar snack[3]={{"mocha munch",2.3,250},{"shdjks",6.3,4546},{"sdf",5.6,497}}; 14 cout<<snack[0].kind<<","<<snack[0].weight<<" ,"<<snack[0].cal<<endl; 15 cout<<snack[1].kind<<","<<snack[1].weight<<" ,"<<snack[1].cal<<endl; 16 cout<<snack[2].kind<<","<<snack[2].weight<<" ,"<<snack[2].cal<<endl; 17 return 0; 18 }
第七题
1 #include<iostream> 2 #include<string> 3 using namespace std; 4 struct Pizza 5 { 6 string company; 7 int d; 8 int weight; 9 }; 10 int main() 11 { 12 Pizza pi; 13 cout<<"enter the information"; 14 cout<<"enter the company "; 15 getline(cin,pi.company); 16 cout<<"enter the d "; 17 cin>>pi.d; 18 cout<<"enter the weight "; 19 cin>>pi.weight; 20 cout<<pi.company<<endl<<pi.d<<endl<<pi.weight<<endl; 21 return 0; 22 }
第八题
1 #include<iostream> 2 #include<string> 3 using namespace std; 4 struct Pizza 5 { 6 string company; 7 int d; 8 int weight; 9 }; 10 int main() 11 { 12 Pizza *pi=new Pizza; 13 14 cout<<"enter the d "; 15 cin>>pi->d; 16 cout<<"enter the company"; 17 getline(cin,pi->company); 18 cout<<"enter the weight "; 19 cin>>pi->weight; 20 21 cout<<pi->company<<endl<<pi->d<<endl<<pi->weight<<endl; 22 return 0; 23 24 }
第九题
1 #include<iostream> 2 #include<string> 3 using namespace std; 4 struct CandyBar 5 { 6 string kind; 7 float weight; 8 int cal; 9 }; 10 11 int main() 12 { 13 CandyBar *ps=new CandyBar[3]; 14 15 ps[0].kind="mocha munch"; 16 ps[0].weight=2.3; 17 ps[0].cal=250; 18 19 ps[1].kind="shdjks"; 20 ps[1].weight=6.3; 21 ps[1].cal=525; 22 23 ps[2].kind="dfsdfs"; 24 ps[2].weight=5.6; 25 ps[2].cal=45; 26 27 cout<<ps->kind<<","<<ps->weight<<" ,"<<ps->cal<<endl; 28 cout<<(ps+1)->kind<<","<<(ps+1)->weight<<" ,"<<(ps+1)->cal<<endl; 29 cout<<(ps+2)->kind<<","<<(ps+2)->weight<<" ,"<<(ps+2)->cal<<endl; 30 31 return 0; 32 }
第十题
1 #include<iostream> 2 #include<string> 3 #include<array> 4 using namespace std; 5 int main() 6 { 7 array<float,3>ps; 8 cout<<"enter the score "; 9 cin>>ps[0]>>ps[1]>>ps[2]; 10 cout<<ps[0]<<ps[1]<<ps[2]<<endl; 11 cout<<(ps[0]+ps[1]+ps[2])/3.0; 12 return 0; 13 }
