js金额转中文大写

基础参数:

var AIW_number = {0:'零', 1:'壹', 2:'贰', 3:'叁', 4:'肆', 5:'伍', 6:'陆', 7:'柒', 8:'捌', 9:'玖'}
var AIW_unitN = ['兆','亿','万','个']
var AIW_unitP = ['厘','分','角']
var AIW_unitU = ['仟','佰','拾','个']

主方法:

function amountInWords(amount) {
 var AIW = (amount+'').split('.')
 if(AIW.length>1)
    return amountInWordsRound(AIW[0])+'元'+amountInWordsF(AIW[1])
 else
     return amountInWordsRound(AIW[0])+'元整'
}

整数部分转换:

function amountInWordsRound(round) {
    if(!round) return ''
    var words = ''
    var rounds = Array.from(round)
    var length = rounds.length
    var unitU = JSON.parse(JSON.stringify(AIW_unitU))
    var unitN = JSON.parse(JSON.stringify(AIW_unitN))
    while(length>0) {
        length--
        A = rounds.pop()
        U = unitU.pop()
        N = (unitU.length==3?unitN.pop():'')
        if(A!=0) words=AIW_number[A]+U+N+words
        else words=AIW_number[A]+N+words
        if(unitU.length==0) unitU = JSON.parse(JSON.stringify(AIW_unitU))
        words = words.replace('undefined','')
        words = words.replace('个','')
    }
    return amountInWordsFormate(words)
}

小数部分转换;

function amountInWordsF(fix) {
    if(!fix) return ''
    var unitP = JSON.parse(JSON.stringify(AIW_unitP));
    var fixs = Array.from(fix)
    var words=''
    $.each(fixs,function(i,o){
        var P = unitP.pop()
        if(o==0) words+=AIW_number[o]
        else words+=AIW_number[o]+P
        words = words.replace('undefined','')
    })
    return amountInWordsFormate(words)
}

格式化处理:

function amountInWordsFormate(words) {
    //去除中位零
    length =  words.length
    while(length>1) {
        length--
        var now = words.charAt(length)
        var before = words.charAt(length-1)
        var after =  words.charAt(length+1)
        if(now == before || (AIW_unitN.includes(after) && now==AIW_number[0] ) ){
            words =  words.substring(0,length)+words.substring(length+1)
            length = words.length
        }
    }
    //去除末位零
    length =  2
    while(length>1) {
        length--
        if(words.charAt(words.length-1)==AIW_number[0] && words.length>1){
            words =  words.substring(0,words.length-1)
            length = 2
        }
    }
    return words
}

 

posted on 2020-06-04 17:43  instr  阅读(2208)  评论(0编辑  收藏  举报

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