作业五
# 1.用列表+循环实现,并包装成函数 def pySum(n): a = list(range(n)) b = list(range(0,5*n,5)) c = [] for i in range(len(a)): c.append(a[i]**2 + b[i]**3) return(c) print(pySum(10)) # 2.用numpy实现,并包装成函数 import numpy def pySum1(n): a=numpy.arange(n) b=numpy.arange(0,5*n,5) c=a+b return (c) print(pySum1(10)) # 3.对比两种方法实现的效率,给定一个较大的参数n,用运行函数前后的timedelta表示。 # from datetime import datetime start = datetime.now() pySum(100000) delta = datetime.now() - start print(delta) start = datetime.now() pySum(100000) delta = datetime.now()-start print(delta)
结果如下: