05 2023 档案
摘要：#include<stdio.h>main(){double s=0,t;int i,n,j;printf("please input the number of n:");scanf("%d",&n);for(i=1;i<=n;i++){t=1;for(j=1;j<=i;j++)t=t*j;s=s
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摘要：#include<stdio.h>void main(){int i,num1,num2,j,n=0;printf("The fraction serials with demominator 40 is:\n");for(i=1;i<40;i++){num1=40;num2=i;for(j=2;j
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摘要：#include<stdio.h>void main(){long int a,b,c;printf("Please enter a optional fraction(a/b):");scanf("%ld%ld",&a,&b);printf("It can be decomposed to:");
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摘要：#include<stdio.h>void main(){int integer,i,max,min,sum;max=-32768;min=32767;sum=0;for(i=0;i<10;i++){printf("Input number %d: ",i);scanf("%d",&integer)
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摘要：#include<stdio.h>main(){int m,n,temp,i;printf("Input m & n:");scanf("%d%d",&m,&n);for(int i=1;;i++){ if(i%m==0&&i%n==0){ printf("%d",i); break; }}retu
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摘要：#include<stdio.h>main(){int m,n,temp,i;printf("Input m&n:");scanf("%d%d",&m,&n);if(m<n){temp=m;m=n;n=temp;}for(i=n;i>0;i--)if(m%i==0&&n%i==0){printf("
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摘要：#include<stdio.h>main(){int i,x,y,last=1;printf("Input x and y:\n");scanf("%d %d",&x,&y);for(i=1;i<=y;i++)last=last*x%1000;printf("The last three digi
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摘要：#include<stdio.h>main(){int i,t,k,a[3]={0};printf("There are following Armstrong number smaller than 1000:\n");for(i=2;i<1000;i++){t=0;k=i;while(k){a[
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摘要：#include<stdio.h>main(){int hun,ten,ind,n;printf("result is:");for(n=100;n<1000;n++){hun=n/100;ten=(n-hun*100)/10;ind=n%10;if(n==hun*hun*hun+ten*ten*t
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摘要：#include<stdio.h>void main(){long mul,number,k,a,b;printf("It exists following automorphic nmbers small than 100000:\n");for(number=0;number<100000;nu
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摘要：#include<stdio.h>void main(){int a,i,b,n;printf("There are following friendly--numbers pair smaller than3000:\n");for(a=1;a<3000;a++){for(b=0,i=1;i<=a
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摘要：#include<stdio.h>main(){int i,j,s,n;printf("请输入所选范围上限:");scanf("%d",&n);for(i=2;i<=n;i++){s=0;for(j=1;j<i;j++){if(i%j==0)s+=j;}if(s==i)printf("It is a
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摘要：#include<stdio.h>main(){int x,y,z,number=0;printf(" Men women Children\n");for(x=0;x<=10;x++){y=20-2*x;z=30-x-y;if(3*x+2*y+z==50)printf("%2d:%4d%5d%6d
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摘要：#include<stdio.h>#include<math.h>main(){double sum=0;int i;for(i=1;i<=64;i++)sum=sum+pow(2,i-1);printf("国王总共需要赏赐给宰相的麦子数为:\n%f\n",sum);}
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摘要：#include<stdio.h>int a[14];main(){int i,j=1,n;printf("魔术师手中的牌原始次序是:\n");for(i=1;i<=13;i++){n=1;do{if(j>13)j=1;if(a[j])j++;else{if(n==i)a[j]=i;j++;n++;
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摘要：#include<stdio.h>main(){long n,sum,i;while(scanf("%ld",&n)!=EOF){printf("在1-%ld之间的阶梯数为:\n",n);sum=0;for(i=7;i<=n;i++)if(i%7==0)if(i%6==5)if(i%5==4)if(
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摘要：#include<stdio.h>int main(){int t,a[5];long int k,i;for(i=98560;;i++){for(t=0,k=100000;k>=10;t++){a[t]=(i%k)/(k/10);k/=10;}if((a[0]==a[4])&&(a[1]==a[3
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