lammps能量单位换算(转载)
转自:https://www.cnblogs.com/Simulation-Campus/p/8823291.html
1 electron-volt [eV] = 11604.5250061657 kelvin [K]
https://www.translatorscafe.com/unit-converter/en/energy/11-65/electron-volt-kelvin/
Constants and Conversion Units
constant | value |
---|---|
h (Planck's constant) | 6.6260755*10-34 J s |
kB (Boltzman's constant) | 1.380658*10-23 J K-1 |
NA (Avogadro's number) | 6.0221367*1023 mol-1 |
c (speed of light) | 2.99792458*1010 cm s-1 |
ao (Bohr radius) | 5.29177249*10-11 m |
e (charge of electron) | 1.60217733*10-19 Coul |
unit | conversion factor |
---|---|
1 Debye | 3.336*10-30 Coul m |
1 eV | 1.60217733*10-19 J |
1 Hartree | 4.3597482*10-18 J |
1 Hartree | 627.509 kcal mol-1 |
1 Hartree | 27.2116 eV |
1 kcal mol-1 | 4.184 J mol-1 |
1 Electron volt | 23.06035 kcal mol-1 |
1 Bohr | 0.529177249 Angstroms |
ZPVE (Hartree) | 2.27817*10-6 * vib. wavenumber (cm-1) |
vibrational temperatur Tv (K) | 1.43877 * vib. wavenumber (cm-1) |
|
如氩分子的能量参数 εar=1.645*10-21J;单位转化为K则为,11604.5250061657/1.60217733*10-19(K/J)*1.645*10-21J=119.8K
单位转化为kcal mol-1则为,1.645*10-21J/个*6.022*1023个/mol/4.184(cal/J)/1000=0.238 kcal/mol
1 kcal/mol=119.8/0.238 K=503.23 K
表面能单位换算:
1ev = 23.0605 Kcal/mol = 1.602176634e-19 J = 1.602176634e-16 mJ
1ev/A2 = 23.0605 ev/A2 = 16021.76634 mj/m2
1Kcal/mol = 6.947695e-21 J = 6.947695e-18 mJ
1Kcal/mol/A2 = 694.7695 mJ/m2,so 23.061 ev/A2 = 16021.7321 mJ/m2 (因为没有用十分精确的数值来计算,结果有点误差,影响不大)