实验6
任务4
源代码
#include<stdio.h> #define N 10 typedef struct { char isbn[20]; char name[80]; char author[80]; double sales_price; int sales_count; }Book; void output(Book x[], int n); void sort(Book x[], int n); double sales_amount(Book x[], int n); int main(){ Book x[N] = {{"978-7-5327-6082-4", "门将之死", "罗纳德.伦", 42, 51}, {"978-7-308-17047-5", "自由与爱之地：入以色列记", "云也退", 49 , 30}, {"978-7-5404-9344-8", "伦敦人", "克莱格泰勒", 68, 27}, {"978-7-5447-5246-6", "软件体的生命周期", "特德姜", 35, 90}, {"978-7-5722-5475-8", "芯片简史", "汪波", 74.9, 49}, {"978-7-5133-5750-0", "主机战争", "布莱克.J.哈里斯", 128, 42}, {"978-7-2011-4617-1", "世界尽头的咖啡馆", "约翰·史崔勒基", 22.5, 44}, {"978-7-5133-5109-6", "你好外星人", "英国未来出版集团", 118, 42}, {"978-7-1155-0509-5", "无穷的开始:世界进步的本源", "戴维·多伊奇", 37.5, 55}, {"978-7-229-14156-1", "源泉", "安.兰德", 84, 59}}; printf("图书销量排名(按销售册数): \n"); sort(x, N); output(x, N); printf("\n图书销售总额: %.2f\n", sales_amount(x, N)); return 0; } void output(Book x[], int n){ int i; Book *p; p = x; printf("ISBN号 书名 作者 售价 销售册数\n"); for(i = 0;i < n; i++){ printf("%-20s%-30s%-20s%-8g%-8d\n",x[i].isbn,x[i].name, x[i].author,x[i].sales_price,x[i].sales_count); } } void sort(Book x[], int n){ int i,j; Book t; for(i = 0;i < n; i++) for(j = 0; j < n - i - 1; j++){ if(x[j].sales_count < x[j + 1].sales_count){ t = x[j]; x[j] = x[j + 1]; x[j + 1] = t; } } } double sales_amount(Book x[], int n){ double s=0; int i; for(i = 0; i < n; i++){ s += x[i].sales_price * x[i].sales_count; } return s; }
运行结果
任务5
源代码
#include <stdio.h> typedef struct { int year; int month; int day; } Date; void input(Date* pd); int day_of_year(Date d); int compare_dates(Date d1,Date d2); void test1() { Date d; int i; printf("输入日期:(以形如2024-12-16这样的形式输入)\n"); for(i = 0;i < 3; i++) { input(&d); printf("%d-%02d-%02d是这一年中的第%d天\n\n",d.year, d.month,d.day,day_of_year(d)); } } void test2() { Date Alice_birth,Bob_birth; int i; int ans; printf("输入Alice和Bob出生日期:(以形如2024-12-16这样的形式输入)\n"); for(i = 0; i < 3; ++i) { input(&Alice_birth); input(&Bob_birth); ans = compare_dates(Alice_birth,Bob_birth); if(ans == 0) printf("Alice和Bob一样大\n\n"); else if(ans == -1) printf("Alice比Bob大\n\n"); else printf("Alice比Bob小\n\n"); } } int main(){ printf("测试1: 输入日期, 打印输出这是一年中第多少天\n"); test1(); printf("\n测试2: 两个人年龄大小关系\n"); test2(); } void input(Date* pd){ scanf("%d-%d-%d",&(pd->year),&(pd->month),&(pd->day)); } int day_of_year(Date d){ int s = 0; if((d.year%4==0&&d.year%100!=0)||d.year%400==0){ if(d.month == 1) s=d.day; else if(d.month == 2) s=31 + d.day; else if(d.month == 3) s=60 + d.day; else if(d.month == 4) s=91 + d.day; else if(d.month == 5) s=121 + d.day; else if(d.month == 6) s=152 + d.day; else if(d.month == 7) s=182 + d.day; else if(d.month == 8) s=213 + d.day; else if(d.month == 9) s=244 + d.day; else if(d.month == 10) s=274 + d.day; else if(d.month == 11) s=305 + d.day; else if(d.month == 12) s=335 + d.day; } else{ if(d.month == 1) s=d.day; else if(d.month == 2) s=31 + d.day; else if(d.month == 3) s=59 + d.day; else if(d.month == 4) s=90 + d.day; else if(d.month == 5) s=120 + d.day; else if(d.month == 6) s=151 + d.day; else if(d.month == 7) s=181 + d.day; else if(d.month == 8) s=212 + d.day; else if(d.month == 9) s=243 + d.day; else if(d.month == 10) s=273 + d.day; else if(d.month == 11) s=304 + d.day; else if(d.month == 12) s=334 + d.day; } return s; } int compare_dates(Date d1,Date d2){ if(d1.year < d2.year) return -1; else if(d1.year > d2.year) return 1; else if(d1.year == d2.year){ if(d1.month < d2.month) return -1; else if(d1.month > d2.month) return 1; else if(d1.month == d2.month) { if(d1.day < d2.day) return -1; else if(d1.day > d2.day) return 1; else if(d1.day == d2.day) return 0; } } }
运行结果
任务6
源代码
#include <stdio.h> #include<string.h> enum Role {admin, student, teacher}; typedef struct { char username[20]; char password[20]; enum Role type; } Account; void output(Account x[], int n); int main(){ Account x[] = {{"A1001", "123456", student}, {"A1002", "123abcdef", student}, {"A1009", "xyz12121", student}, {"X1009", "9213071x", admin}, {"C11553", "129dfg32k", teacher}, {"X3005", "921kfmg917", student}}; int n; n = sizeof(x)/sizeof(Account); output(x, n); return 0; } void output(Account x[], int n) { int len,i,j; for(i = 0; i < n; i++){ len = strlen(x[i].password); for(j = 0; j < len; j++){ x[i].password[j]='*'; } } for(i = 0; i < n; i++){ printf("%-20s%-20s",x[i].username,x[i].password); if((enum Role)x[i].type==0) printf("admin\n"); else if((enum Role)x[i].type==1) printf("student\n"); else printf("teacher\n"); } }
运行结果
任务7
源代码
#include <stdio.h> #include <string.h> #define N 10 typedef struct { char name[20]; char phone[12]; int vip; }Contact; void set_vip_contact(Contact x[], int n, char name[]); void output(Contact x[], int n); void display(Contact x[], int n); int main(){ Contact list[N] = {{"刘一", "15510846604", 0}, {"陈二", "18038747351", 0}, {"张三", "18853253914", 0}, {"李四", "13230584477", 0}, {"王五", "15547571923", 0}, {"赵六", "18856659351", 0}, {"周七", "17705843215", 0}, {"孙八", "15552933732", 0}, {"吴九", "18077702405", 0}, {"郑十", "18820725036", 0}}; int vip_cnt, i; char name[20]; printf("显示原始通讯录信息: \n"); output(list,N); printf("\n输入要设置的紧急联系人个数: "); scanf("%d", &vip_cnt); printf("输入%d个紧急联系人姓名:\n", vip_cnt); for(i = 0; i < vip_cnt; i++){ scanf("%s",name); set_vip_contact(list, N, name); } printf("\n显示通讯录列表:(按姓名字典序升序排列,紧急联系人最先显示)\n"); display(list, N); return 0; } void set_vip_contact(Contact x[], int n, char name[]){ int i = 0; for(i = 0; i < n; i++){ if(strcmp(x[i].name,name) == 0){ x[i].vip = 1; } } } void output(Contact x[], int n){ int i; for(i = 0;i < n; i++) { printf("%-10s%-15s",x[i].name,x[i].phone); if(x[i].vip==1) printf("%5s","*"); printf("\n"); } } void display(Contact x[], int n){ int i,j=0,cnt=0; Contact t; for(i = 0; i < n; i++){ if(x[i].vip == 1){ cnt++; t = x[j]; x[j] = x[i]; x[i] = t; j++; } } for(i = 0; i < cnt; i++){ for(j = 0; j < cnt - 1 - i; j++){ if(strcmp(x[j].name,x[j + 1].name)>0){ t = x[j]; x[j] = x[j+1]; x[j+1] = t; } } } for(i = 0; i < n; i++){ for(j = cnt; j < n - 1 - i; j++){ if(strcmp(x[j].name,x[j + 1].name)>0){ t = x[j]; x[j] = x[j+1]; x[j+1] = t; } } } output(x, n); }
运行结果
