JS获取url参数

    GetRequest() {
      var url = location.search; //获取url中"?"符后的字串
      var theRequest = new Object();
      if (url.indexOf("?") != -1) {
        var str = url.substr(1);
        var strs = str.split("&");
        for(var i = 0; i < strs.length; i ++) {
          theRequest[strs[i].split("=")[0]]=unescape(strs[i].split("=")[1]);
        }
      }
      return theRequest;
    }

  

posted @ 2020-08-20 15:02  syqaily  阅读(114)  评论(0编辑  收藏  举报