历法的转换。
1 #include <stdio.h> 2 #include <math.h> 3 #include <string.h> 4 char Haab[19][10]={ 5 "pop","no","zip","zotz","tzec","xul","yoxkin","mol", 6 "chen","yax","zac","ceh","mac","kankin","muan","pax", 7 "koyab","cumhu","uayet" 8 }; 9 char Tzolkin[20][10]={ 10 "imix","ik","akbal","kan","chicchan","cimi","manik", 11 "lamat","muluk","ok","chuen","eb","ben","ix","mem", 12 "cib","caban","eznab","canac","ahau" 13 }; 14 int count(int day,char month[],int year){ 15 int tot=0; 16 tot+=(day+1); 17 int i; 18 for(i=0;i<19;++i){ 19 if(strcmp(month,Haab[i])==0){ 20 tot+=(i*20); 21 break; 22 } 23 } 24 tot+=(year*365); 25 return tot; 26 } 27 int main(){ 28 int t,i,tot; 29 int day,year; 30 int m; 31 char month[10]; 32 while(~scanf("%d",&t)){ 33 printf("%d\n",t); 34 for(i=0;i<t;++i){ 35 scanf("%d. %s %d",&day,month,&year); 36 tot=count(day,month,year); 37 m=(tot-1)%20; 38 day=(tot-1)%13; 39 day++; 40 if(day>13){ 41 day=(day%13)+1; 42 }else 43 year=(tot-1)/260; 44 printf("%d %s %d\n",day,Tzolkin[m],year); 45 } 46 } 47 return 0; 48 }
