设计模式-创建型-静态工厂模式

   刚开始接触编程时,总会提到设计模式,在这里将一般定义的设计模式一一进行说明,先从简单的设计模式开始。

        创建型-静态工厂模式(并不是Gof得23中设计模式,后来人们扩展的,尽信书不如无书,这也体现了JAVA的魅力)

  假设有这样一个工厂,可以生产几种不同类型的笔;我们只向工厂说明一下我们需要的笔型号,工厂就给我们提供相应型号的笔。

  假设我们有一个工厂对象(ShapeFactory),可以建几种不同样式的外形(Shape);我们只向工厂对象(ShapeFactory)传我们需要创建的外形(Shape)的参数(如描述参数),对象(ShapeFactory)就给我们创建不同的外形(Shape)。

  本文引用W3Cschool中的java教程中设计模式,链接地址https://www.w3cschool.cn/java/java-factory-pattern.html

  外形Shape的接口

 Shape.java
  public interface Shape {

     void draw();

  }

  不同类型的外形对象,即Shape接口的实现类

  Rectangle.java

  public class Rectangle implements Shape {
    @Override
    public void draw() {
      System.out.println("Inside Rectangle::draw() method.");
    }
  }

  Square.java

  public class Square implements Shape {
    @Override
    public void draw() {
      System.out.println("Inside Square::draw() method.");
    }
  }

  工厂生产的外形(Shape)有了,几种简单的Shape实现类有了(即几种不同的外形),现在就缺少工厂对象(ShapeFactory)了。工厂对象ShapeFactory中我们需要提供一个方法,用来生产几种不同的外形对象。本文方法为getShape(String shapestyle)。

  ShapeFactory.java

public class ShapeFactory {
    public static Shape getShape(String shapestyle) {
        if(shapestyle==null) {
            return null;
        }
        if("Rectangle".equalsIgnoreCase(shapestyle)) {
            return new Rectangle();
        }
        if ("Square".equalsIgnoreCase(shapestyle)) {
            return new Square() ;
        }
        return null;
    }
}

 

     好了,到现在为止,我们的工厂已经建好了。怎样用这个工厂呢,现在需要用工厂得到一个Square对象,也比较简单了。在ShapeFactoryTest类中,用ShapeFactory 创建Square对象为例子

  ShapeFactoryTest.java

public class ShapeFactoryTest {
    public static void main(String[] args) {
        Shape shape = ShapeFactory.getShape("Square");
        shape.drow();
    }
}

  程序运行结果

Inside Square::draw() method.

综上,一个静态工厂模式已经完成了。

为什么说ShapeFactoryTest就是静态工厂了呢,这样编程怎么就是静态工厂模式呢?
因为我们自己不单独new
Square()和new Rectangle()对象,这个对象由ShapeFactoryTest创建(生产),创建时使用静态方法,所以这种设计的方式被大家叫做静态工厂模式。 
为什么要用静态工厂模式呢?在本例子中,不通过Shape shape = shapeFactory.getShape("Square")方式获取Square对象,而是直接用new Square()获取Square对象,不是也行吗?
先回答第二个问题,直接用Shape shape =new Square()的方式获取Shape的实现确实也可行。

再看第一个问题,shapeFactory.getShape("Square")中Square参数是我们直接写的,如果这个参数是外部传递的参数呢?外部传递的参数可能是Square,也可能是Rectangle,这时我们不知道外部传递
什么参数,执行的方法与传参有关,这时候一个静态工厂模式就是需要的了。

对于刚开始接触java的人,这种静态工厂我们有没有接触过呢?
JavaSE是我们学习java是最先接触到的知识了,其实JaveSE中体现了很多种设计模式。在java.nio中,Paths中就包含了两个返回Path对象的静态工厂方法:
Path path1 = Paths.get(URI uri);
Path path2 = Paths.get(String first,String... more);
具体使用也比较简单,大家可以自己写一个简单的Class,在main方法中使用Path path1 = Paths.get(".");导入相应的包之后,查看源代码,看Paths类,相信大家会感觉静态工厂方法其实离我们不远,对
静态工厂方法的体会更加深刻。

例子
public class PathsTest {
    public static void main(String[] args) {
        Path path = Paths.get(".");
    }
}

Paths源码

package java.nio.file;

import java.nio.file.spi.FileSystemProvider;
import java.net.URI;

/**
 * This class consists exclusively of static methods that return a {@link Path}
 * by converting a path string or {@link URI}.
 *
 * @since 1.7
 */

public final class Paths {
    private Paths() { }

    /**
     * Converts a path string, or a sequence of strings that when joined form
     * a path string, to a {@code Path}. If {@code more} does not specify any
     * elements then the value of the {@code first} parameter is the path string
     * to convert. If {@code more} specifies one or more elements then each
     * non-empty string, including {@code first}, is considered to be a sequence
     * of name elements (see {@link Path}) and is joined to form a path string.
     * The details as to how the Strings are joined is provider specific but
     * typically they will be joined using the {@link FileSystem#getSeparator
     * name-separator} as the separator. For example, if the name separator is
     * "{@code /}" and {@code getPath("/foo","bar","gus")} is invoked, then the
     * path string {@code "/foo/bar/gus"} is converted to a {@code Path}.
     * A {@code Path} representing an empty path is returned if {@code first}
     * is the empty string and {@code more} does not contain any non-empty
     * strings.
     *
     * <p> The {@code Path} is obtained by invoking the {@link FileSystem#getPath
     * getPath} method of the {@link FileSystems#getDefault default} {@link
     * FileSystem}.
     *
     * <p> Note that while this method is very convenient, using it will imply
     * an assumed reference to the default {@code FileSystem} and limit the
     * utility of the calling code. Hence it should not be used in library code
     * intended for flexible reuse. A more flexible alternative is to use an
     * existing {@code Path} instance as an anchor, such as:
     * <pre>
     *     Path dir = ...
     *     Path path = dir.resolve("file");
     * </pre>
     *
     * @param   first
     *          the path string or initial part of the path string
     * @param   more
     *          additional strings to be joined to form the path string
     *
     * @return  the resulting {@code Path}
     *
     * @throws  InvalidPathException
     *          if the path string cannot be converted to a {@code Path}
     *
     * @see FileSystem#getPath
     */
    public static Path get(String first, String... more) {
        return FileSystems.getDefault().getPath(first, more);
    }

    /**
     * Converts the given URI to a {@link Path} object.
     *
     * <p> This method iterates over the {@link FileSystemProvider#installedProviders()
     * installed} providers to locate the provider that is identified by the
     * URI {@link URI#getScheme scheme} of the given URI. URI schemes are
     * compared without regard to case. If the provider is found then its {@link
     * FileSystemProvider#getPath getPath} method is invoked to convert the
     * URI.
     *
     * <p> In the case of the default provider, identified by the URI scheme
     * "file", the given URI has a non-empty path component, and undefined query
     * and fragment components. Whether the authority component may be present
     * is platform specific. The returned {@code Path} is associated with the
     * {@link FileSystems#getDefault default} file system.
     *
     * <p> The default provider provides a similar <em>round-trip</em> guarantee
     * to the {@link java.io.File} class. For a given {@code Path} <i>p</i> it
     * is guaranteed that
     * <blockquote><tt>
     * Paths.get(</tt><i>p</i><tt>.{@link Path#toUri() toUri}()).equals(</tt>
     * <i>p</i><tt>.{@link Path#toAbsolutePath() toAbsolutePath}())</tt>
     * </blockquote>
     * so long as the original {@code Path}, the {@code URI}, and the new {@code
     * Path} are all created in (possibly different invocations of) the same
     * Java virtual machine. Whether other providers make any guarantees is
     * provider specific and therefore unspecified.
     *
     * @param   uri
     *          the URI to convert
     *
     * @return  the resulting {@code Path}
     *
     * @throws  IllegalArgumentException
     *          if preconditions on the {@code uri} parameter do not hold. The
     *          format of the URI is provider specific.
     * @throws  FileSystemNotFoundException
     *          The file system, identified by the URI, does not exist and
     *          cannot be created automatically, or the provider identified by
     *          the URI's scheme component is not installed
     * @throws  SecurityException
     *          if a security manager is installed and it denies an unspecified
     *          permission to access the file system
     */
    public static Path get(URI uri) {
        String scheme =  uri.getScheme();
        if (scheme == null)
            throw new IllegalArgumentException("Missing scheme");

        // check for default provider to avoid loading of installed providers
        if (scheme.equalsIgnoreCase("file"))
            return FileSystems.getDefault().provider().getPath(uri);

        // try to find provider
        for (FileSystemProvider provider: FileSystemProvider.installedProviders()) {
            if (provider.getScheme().equalsIgnoreCase(scheme)) {
                return provider.getPath(uri);
            }
        }

        throw new FileSystemNotFoundException("Provider \"" + scheme + "\" not installed");
    }
}

 

posted on 2019-05-14 16:32  xingshouzhan  阅读(182)  评论(0编辑  收藏  举报

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