摘要: select (@i:=@i+1) i,emp.* from emp,(select @i:=0) it 按部门分组并按薪资总和从大到小排序求薪资总和第二高的部门名称和薪资总和: SELECT c.ename, c.s FROM ( SELECT ( @i := @i + 1 ) i, e.* FR 阅读全文
posted @ 2019-11-20 20:34 玩转大数据 阅读(5072) 评论(0) 推荐(1) 编辑
摘要: hdfs fsck / Connecting to namenode via http://localhost:9870/fsck?ugi=liugen&path=%2FFSCK started by liugen (auth:SIMPLE) from /127.0.0.1 for path / a 阅读全文
posted @ 2019-11-20 10:02 玩转大数据 阅读(696) 评论(0) 推荐(0) 编辑