LeetCode-Clone Graph
Clone an undirected graph. Each node in the graph contains a label
and a list of its neighbors
.
OJ's undirected graph serialization:
Nodes are labeled uniquely.
We use #
as a separator for each node, and ,
as a separator for node label and each neighbor of the node.
As an example, consider the serialized graph {0,1,2#1,2#2,2}
.
The graph has a total of three nodes, and therefore contains three parts as separated by #
.
- First node is labeled as
0
. Connect node0
to both nodes1
and2
. - Second node is labeled as
1
. Connect node1
to node2
. - Third node is labeled as
2
. Connect node2
to node2
(itself), thus forming a self-cycle.
Visually, the graph looks like the following:
1 / \ / \ 0 --- 2 / \ \_/
class Solution { public: void Sub(map<UndirectedGraphNode*,UndirectedGraphNode*>& se,UndirectedGraphNode** nnode,UndirectedGraphNode*node){ (*nnode)=new UndirectedGraphNode(node->label); se[node]=(*nnode); for(int i=0;i<node->neighbors.size();i++){ if(se.find(node->neighbors[i])==se.end()){ UndirectedGraphNode * n; Sub(se,&n,node->neighbors[i]); (*nnode)->neighbors.push_back(n); } else{ (*nnode)->neighbors.push_back(se[node->neighbors[i]]); } } } UndirectedGraphNode *cloneGraph(UndirectedGraphNode *node) { // Note: The Solution object is instantiated only once and is reused by each test case. if(node==NULL)return NULL; UndirectedGraphNode * ret=NULL; map<UndirectedGraphNode *,UndirectedGraphNode*>se; Sub(se,&ret,node); return ret; } };