uva 488 Triangle Wave
Description
Triangle Wave |
In this problem you are to generate a triangular wave form according to a specified pair of Amplitude and Frequency.
Input and Output
The input begins with a single positive integer on a line by itself indicating the number of the cases following, each of them as described below. This line is followed by a blank line, and there is also a blank line between two consecutive inputs.
Each input set will contain two integers, each on a separate line. The first integer is the Amplitude; the second integer is the Frequency.
For each test case, the output must follow the description below. The outputs of two consecutive cases will be separated by a blank line.
For the output of your program, you will be printing wave forms each separated by a blank line. The total number of wave forms equals the Frequency, and the horizontal ``height'' of each wave equals the Amplitude. The Amplitude will never be greater than nine.
The waveform itself should be filled with integers on each line which indicate the ``height'' of that line.
NOTE: There is a blank line after each separate waveform, excluding the last one.
Sample Input
1 3 2
Sample Output
1 22 333 22 1 1 22 333 22 1
#include<bits/stdc++.h> using namespace std; int main() { int n; cin>>n; while(n--) { int amp,fre; cin>>fre>>amp; //cout<<endl; for(int i=0;i<amp;i++) { for(int j=1;j<=fre;j++) { int t=j; while(t--) cout<<j; cout<<endl; } for(int j=fre-1;j>=1;j--) { int t=j; while(t--) cout<<j; cout<<endl; } //cout<<"n="<<n<<endl; //cout<<"sss"; if(i<amp-1)cout<<endl; } if(n>0) cout<<endl; } return 0; }
主要是读懂题目的输出格式,每组测试样例之间要有空格,除了最后一组波外,每个波之间要有空行。