实验4
=======================================第一题=======================================================================
#include <stdio.h> const int N = 4; int main() { int a[N] = { 2, 0, 2, 1 }; // 定义一个int型数组a,包含N个元素 char b[N] = { '2', '0', '1', '1' }; // 定义一个char型数组a,包含N个元素 int i; printf("sizeof(int) = %d\n", sizeof(int)); printf("sizeof(char) = %d\n", sizeof(char)); printf("\n"); // 输出数组a中每个元素的地址(以十六进制显示)、元素值 for (i = 0; i < N; ++i) printf("%x: %d\n", &a[i], a[i]); printf("\n"); // 输出数组b中每个元素的地址(以十六进制显示)、元素值 for (i = 0; i < N; ++i) printf("%x: %c\n", &b[i], b[i]); return 0; }
1.int型连续存放,每个元素占4个字节
2.char型连续存放,每个元素占1个字节
#include <stdio.h> int main() { int a[2][3] = { {1, 2, 3}, {4, 5, 6} }; char b[2][3] = { {'1', '2', '3'}, {'4', '5', '6'} }; int i, j; // 输出二维数组a中每个元素的地址(以十六进制显示)、元素值 for (i = 0; i < 2; ++i) for (j = 0; j < 3; ++j) printf("%x: %d\n", &a[i][j], a[i][j]); printf("\n"); // 输出二维数组b中每个元素的地址(以十六进制显示)、元素值 for (i = 0; i < 2; ++i) for (j = 0; j < 3; ++j) printf("%x: %c\n", &b[i][j], b[i][j]); }
1.int型二维数组连续存放,每个元素占4个字节
2’。char型二维数组连续存放,每个元素占1个字节
=======================================第二题=============================================================
#include <stdio.h> #define N 1000 int fun(int n, int m, int bb[N]) { int i, j, k = 0, flag; for (j = n; j <= m; j++) { flag=1; for (i = 2; i < j; i++) if (j%i==0) { flag = 0; break; } if (flag==1) bb[k++] = j; } return k; } int main() { int n = 0, m = 0, i, k, bb[N]; scanf_s("%d", &n); scanf_s("%d", &m); for (i = 0; i < m - n; i++) bb[i] = 0; k = fun(n,m,bb); for (i = 0; i < k; i++) printf("%4d", bb[i]); return 0; }
===========================================第三题========================================================
#include <stdio.h> const int N = 5; int find_max(int x[], int n); void input(int x[], int n); void output(int x[], int n); int main() { int a[N]; int max; input(a, N); // 调用input完成数组输入 output(a, N); // 调用output输出数组元素值 max = find_max(a, N); // 调用find_max查找数组a的最大值 printf("max = %d\n", max); return 0; } // 函数定义 // 功能:为数组x的n个元素输入数值 void input(int x[], int n) { int i; for (i = 0; i < n; ++i) scanf_s("%d", &x[i]); } // 函数定义 // 功能:输出数组x中的n个元素 void output(int x[], int n) { int i; for (i = 0; i < n; ++i) { printf("%d ", x[i]); } printf("\n"); } int find_max(int x[], int n) { int i,max=0; for (i = 0; i < n; i++) { if (max < x[i]) { max = x[i]; } } return max; }
================================================================第四题===============================================
#include <stdio.h> void dec2n(int x, int n); // 函数声明 int main() { int x; printf("输入一个十进制整数: "); scanf_s("%d", &x); dec2n(x, 2); // 函数调用: 把x转换成二进制输出 dec2n(x, 8); // 函数调用: 把x转换成八进制输出 dec2n(x, 16); // 函数调用: 把x转换成十六进制输出 return 0; } void dec2n(int x, int n) { int j,b[100]; int i = 0; do { b[i] = x % n; x = x / n; i++; } while (x != 0); for (j = i - 1; j >= 0; j--) { if (b[j] < 10) { printf("%d", b[j]); } else { printf("%c", b[j] + 55); } } printf("\n"); }
=======================================================第六题============================================================
#include<stdio.h> #include<stdlib.h> #define N 100 void fun(int x[N][N], int n) { int i, j; for (i = 1; i <= n; i++) for (j = 1; j <= n; j++) if (i <= j) x[i][j] = i; else x[i][j] = j; } int main() { int n, i, j, a[N][N]; scanf_s("%d", &n); fun(a, n); for (i = 1; i <= n; i++) { for (j = 1; j <= n; j++) { printf("%d ", a[i][j]); } printf("\n"); } system("pause"); return 0; }