JDK5.0 特性-线程同步装置之Semaphore
来自:http://www.cnblogs.com/taven/archive/2011/12/17/2291474.html
1 import java.util.ArrayList; 2 3 import java.util.concurrent.ExecutorService; 4 5 import java.util.concurrent.Executors; 6 7 import java.util.concurrent.Semaphore; 8 9 import java.util.concurrent.locks.Lock; 10 11 import java.util.concurrent.locks.ReentrantLock; 12 13 14 15 /** 16 17 *Java 5.0里新增加了4个协调线程间进程的同步装置,它们分别是:Semaphore,CountDownLatch,CyclicBarrier和Exchanger 18 19 *Semaphore可以控制运行线程的个数 20 21 *Semaphore是一个用来管理资源池的工具,可以看成是个通行证,线程要想从资源池拿到资源必须先拿到通行证,如果线程暂时拿不到通告证,线程就会被阻断,进入等待状态. 22 23 */ 24 25 /** 26 27 *使用Semaphore的关键技术点如下: 28 29 *1.在构造Semaphore对象时,必须提供通行证的数目,如"newSemaphore(3)"将创建一个具有3个通行证的Semaphore对象,一旦该对象被创建,其通行证数量是不能改变的. 30 31 *2.Semaphore的acquire方法取得一个通行证,如果通行证已经发完了,当前线程将进入等待状态,直到有其他线程释放了通行证. 32 33 *3.Semaphore的release方法释放了资源池. 34 35 */ 36 37 public class SemaphoreTest { 38 39 /** 40 41 * 模拟资源池的类 42 43 * 只为池发放2个通行证,即同时只允许2个线程获得池中的资源 44 45 */ 46 47 public static class Pool{ 48 49 ArrayList<String> pool = null; //保存资源池中的资源 50 51 Semaphore pass = null; //通行证 52 53 Lock lock = new ReentrantLock(); 54 55 public Pool(int size){ 56 57 //初始化资源池 58 59 pool = new ArrayList<String>(); 60 61 for(int i = 0; i < size; i++){ 62 63 pool.add("Resource " + i); 64 65 } 66 67 //发送2个通行证 68 69 pass = new Semaphore(2); 70 71 } 72 73 public String get()throws InterruptedException{ 74 75 //获取通行证,只有得到通行证后才能得到资源 76 77 System.out.println("Try to get a pass..."); 78 79 pass.acquire(); 80 81 System.out.println("Got a pass"); 82 83 return getResource(); 84 85 } 86 87 private String getResource(){ 88 89 lock.lock(); 90 91 String result = pool.remove(0); 92 93 System.out.println("资源 " + result + "被取走"); 94 95 lock.unlock(); 96 97 return result; 98 99 } 100 101 public void put(String resource){ 102 103 //归还通行证,并那还资源 104 105 System.out.println("Released a pass"); 106 107 pass.release(); 108 109 releaseResource(resource); 110 111 } 112 113 private void releaseResource(String resource){ 114 115 lock.lock(); 116 117 System.out.println("资源 " + resource + " 被归还"); 118 119 pool.add(resource); 120 121 lock.unlock(); 122 123 } 124 125 } 126 127 public static void testPool(){ 128 129 //准备10个资源的资源池 130 131 final Pool aPool = new Pool(10); 132 133 Runnable worker = new Runnable(){ 134 135 @Override 136 137 public void run() { 138 139 String resource = null; 140 141 try{ 142 143 resource = aPool.get();//取得resource 144 145 //用resource做工作 146 147 System.out.println("I finished on " + resource); 148 149 Thread.sleep(500); 150 151 System.out.println("I finished on " + resource); 152 153 }catch(InterruptedException ex){ 154 155 } 156 157 aPool.put(resource); 158 159 } 160 161 }; 162 163 //启动5个任务 164 165 ExecutorService service = Executors.newCachedThreadPool(); 166 167 for(int i = 0; i<5; i++){ 168 169 service.submit(worker); 170 171 } 172 173 service.shutdown(); 174 175 } 176 177 public static void main(String... args){ 178 179 SemaphoreTest.testPool(); 180 181 } 182 183 }